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Artyom0805 [142]
3 years ago
9

Hector is visiting a cousin who lives 400 miles away he has driven 75 miles how many more miles does he need to drive to reach h

is cousin’s home let d be how many miles left to reach his cousins house
Mathematics
1 answer:
natali 33 [55]3 years ago
4 0

Answer: Hector needs to drive 325 more miles.

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Points A, R and G are points of tangency. Find the perimeter of ∆NET below.
Paha777 [63]

Answer:

\small\mathfrak\red{here \: is \: your \: solution..} \\  \\ we \: know \: that \: tangent \\ from \: a \: same  point \: are \: equal \\  \\ tr = 9 | an = 7 |  eg = 5 \\  \\ tr = ta | an = gn | eg = re \\  \\ ta = 9 |  gn =7 | re = 5 \\  \\ hence \: perimeter \:  = 2(9 + 7 + 5) \\  \\ perimeter = 42 \:  \\  \\ \huge\mathfrak\purple{hope \: it \: helps...}

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3 years ago
Donna the trainer has two solo workout plans that she offers her clients: Plan A and Plan B. Each client does either one or the
kykrilka [37]
X=hours of plan A
y=hours of plan B

wed: 5x+6y=12
thu: 3x+2y=6

so
5x+6y=12 and
3x+2y=6
we can eliminate y's by multiplying 2nd equation by -3 and adding to first equation

-9x-6y=-18
<u>5x+6y=12 +</u>
-4x+0y=-6

-4x=-6
divid both sides by -4
x=-6/-4
x=3/2
x=1.5

sub back

3x+2y=6
3(1.5)+2y=6
4.5+2y=6
2y=1.5
y=0.75



Plan A=1.5 hours
Plan B=0.75 hours
3 0
2 years ago
answer correctly for 70 points but if rong i will report u and get all ur points and mine back and u banned
12345 [234]

Answer:

11) 0.6

12) The maximum height of the ball was 2[ seconds] after it was thrown (I am assuming because the answers are cut off a bit.)

13) $2.50

14) (2,-15)

15) I don't know, since I can't see all the graphs and options. But I want to say the sideways parabola, or the only one shown in the image given

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B12%7D%20%2B4%5Csqrt%7B25%7D%20-%5Csqrt%7B108%7D%20-%5Cfrac%7B1%7D%7B4%7D%20%5Csqrt%7
Eduardwww [97]

20−6√3

Step by step Explanation:

√12+4√25−√108−1/4 √192

2√3+4×5-√108-2√3

2√3+20-√108-2√3

20−6√3

7 0
2 years ago
Read 2 more answers
The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales
andrezito [222]

Answer:

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=44 represent the sample mean

s=1.9 represent the sample standard deviation

n=40 sample size  

\mu_o =42 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 42, the system of hypothesis would be:  

Null hypothesis:\mu \leq 42  

Alternative hypothesis:\mu > 42  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{44-42}{\frac{1.9}{\sqrt{40}}}=6.657    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>6.657)=3.17x10^{-8}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 42 at 1% of signficance.  

3 0
3 years ago
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