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beks73 [17]
3 years ago
6

For every 7 glasses wearers in a Classroom,there are about 13 non glasses wearers.If there are 32 students in a entire class how

many students are non glasses wearers
Mathematics
1 answer:
Alla [95]3 years ago
6 0

Answer:

21 With glasses

Step-by-step explanation:

32/20=1.6

1.6•7=11.2 Without Glasses

1.6•13=20.8 With Glasses

20.8 rounded to nearest whole number=21

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Tre'Quan reads at a constant rate that lets him complete 4 chapters each week. He starts reading a book with 42 chapters. Which
Tju [1.3M]

Answer:

y=42− 4/7 x

Step-by-step explanation:

4 0
2 years ago
Due tomarrow please help!!!!!!!!!!!!!!!!!!!!!!!!!  Identify the independent and dependent variables in the following statement.
BlackZzzverrR [31]
The independent variable is the variable that is being changed. In this statement, it would be water flowing flowing in the pool. The dependent variable is what is being changed so that would be the depth of the water.

There, I hope this helps! :)

6 0
3 years ago
Which expression represents a number, p, added to the difference of 25 and 5?
blsea [12.9K]
A, it correctly shows p added to 25-5.
3 0
3 years ago
Read 2 more answers
If the volume of a box is 2x3 + 4x2 − 30xwhich of the dimensions are possible with the given x-value?
Kipish [7]

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

Step-by-step explanation:

The given is,

                        2 x^{3} + 4 x^{2} -30x................................(1)

Step:1

    Check for option A,

             x = 1, dimensions 8 by 9 by 1  

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(2)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                     = 72............................................(3)

            From equation (2) and (3)

                                -24 ≠ 72

            So, X=1; dimensions 8 by 9 by 1 is not possible.

   Check for option B,

             x = 1, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(4)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30.........................................(5)

            From equation (4) and (5)

                                -24 ≠ 30

            So, X=1; dimensions 2 by 5 by 3 is not possible.

   Check for option C,

            x = 4, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72.............................................(6)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30............................................(7)

            From equation (6) and (7)

                               72 ≠ 30

            So, X=4; dimensions 2 by 5 by 3 is not possible.

    Check for option C,

            x = 4, dimensions 8 by 9 by 1

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72............................................(8)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                    = 72............................................(9)

            From equation (8) and (9)

                               72 = 72

            So, X=4; dimensions 8 by 9 by 3 is possible.

Result:

           The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

         

4 0
3 years ago
You have a bag with 10 pennies, 10 quarters, and 10 dimes. You draw 2 coins without replacement. Which action, performed before
Nitella [24]

Answer:

Removing pennies and dimes from the bag

Step-by-step explanation:

From the beginning, we have a 1 in 3 chance of drawing a quarter. If we were to add dimes and/or pennies to the bag, this would make us more likely to draw a dime or a penny, and less likely to draw a quarter. Proportionally, we want the most quarters in the bag to get the highest probability of drawing a quarter from the bag.

8 0
3 years ago
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