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valina [46]
3 years ago
11

Whats number one if somone can help plz

Mathematics
2 answers:
denpristay [2]3 years ago
4 0
Its A hope this helped you
Veseljchak [2.6K]3 years ago
3 0
The Answer is A..............................

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Solve the following:<br> a. 4x^2 + 5x + 3 = 2x^2 − 3x<br> b. c^2 − 14 = 5c
Jet001 [13]

Answer:

(a) x = -0.418 , -3.581

(B) c = 6.855, -1.855

Step-by-step explanation:

(A) We have given equation 4x^2+5x+3=2x^2-3x

2x^2+8x+3=0

On comparing with standard quadratic equation ax^2+bx+c

a = 2, b = 8 and c = 3

So roots of the equation will be x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-8\pm \sqrt{8^2-4\times 2\times 3}}{2\times 2}=\frac{-8\pm 6.324}{4}=-0.418,-3.581

(b) c^2-14=5c

c^2-5c-14=0

a = 1, b = -5 and c= -14

So c=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-(-5)\pm \sqrt{(-5)^2-4\times 1\times (-14)}}{2\times 1}=\frac{5\pm 8.71}{2}=6.855,-1.855

7 0
3 years ago
5. Two similar figures have volumes 27 in.? and 125 in.?. The surface area of the smaller figure is 63 in.. (1 point)
GREYUIT [131]

Answer:

175\ in^{2}

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the larger solid

y----> volume of the smaller solid

z^{3}=\frac{x}{y}

we have

x=125\ in^{3}

y=27\ in^{3}

substitute

z^{3}=\frac{125}{27}

z=\frac{5}{3}

step 2

Find the surface area of the larger solid

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the larger solid

y----> surface area of the smaller solid

z^{2}=\frac{x}{y}

we have

z=\frac{5}{3}

y=63\ in^{2}

substitute

(\frac{5}{3})^{2}=\frac{x}{63}

x=\frac{25}{9}*63=175\ in^{2}

3 0
3 years ago
If f(x)=x+7 and g(x)= 1 divided by x-13, what is the domain of (f•g)(x)?
andrew11 [14]
<h2>Hello!</h2>

The answer is:

The domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

<h2>Why?</h2>

This is a composite function problem. To solve it, we need to remember how to composite a function. Composing a function consists of evaluating a function into another function.

Composite function is equal to:

f(g(x))=(f\circ} g)(x)

So, the given functions are:

f(x)=x+7\\\\g(x)=\frac{1}{x-13}

Then, composing the functions, we have:

f(g(x))=\frac{1}{x-13}+7\\

Therefore, we must remember that the domain are all those possible inputs where the function can exists, most of the functions can exists along the real numbers with no rectrictions, however, for this case, there is a restriction that must be applied to the resultant composite function.

If we evaluate "x" equal to 13, the denominator will tend to 0, and create an indetermination since there is no result in the real numbers for a real number divided by 0.

So, the domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

Have a nice day!

5 0
3 years ago
I need help on this and more so can sb help me ?..
nignag [31]

Answer:

Its the 2nd one

Step-by-step explanation:

Simplify the exponents and then multiply

4 0
3 years ago
What is 825 divided by 7
grandymaker [24]
825 ÷ 7 = <span>117.857142857
hope i helped!!!!!</span>
6 0
2 years ago
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