Answer:volume of regular pyramid = 3388 units³
Explanation:Volume of regular pyramid can be calculated using the following rule:
volume of regular pyramid =

* area of base * height
volume of regular pyramid =

* length * width * height
Based on the comment you added above, we have:
length = 11 units
width = 11 units
height = 84 units
Substitute with the givens in the above equation to get the volume as follows:
volume =

* 11 * 11 * 84
volume = 3388 units³
Hope this helps :)
30 = 3/5
so 1/5 = 10 miles
there are 20/5 in 4 inches
10*20 = 200
they are 200 miles apart
The magnitude of each vector is the Pythagorean sum of its components.
a. |v1| = √(2² + (-6)²) = √40 = 2√10
|v2| = √((-4)² + 7²) = √65
b. To make each vector into a unit vector, divide each component by the vector's magnitude.
u1 = v1/|v1| = (2/(2√10), -6/(2√10))
u1 = (√10/10, -3√10/10)
u2 = v2/|v2| = (-4/√65, 7/√65)
u2 = (-4√65/65, 7√65/65)
Answer:
The end of the flagpole is 50.79 ft away from the base of the pole.
Step-by-step explanation:
The problem is represented by the diagram below.
The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).
The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).
Using Pythagoras theorem, we have that:

=> 

The end of the flagpole is 50.79 ft away from the base of the pole.
The total number of employees are 80. I know that because 25 is quarter of 100 and if 20 employees are 25%, all I need to do is 20*4 which is 80. Hope this helped!