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wlad13 [49]
3 years ago
10

I need help on this and more so can sb help me ?..

Mathematics
1 answer:
nignag [31]3 years ago
4 0

Answer:

Its the 2nd one

Step-by-step explanation:

Simplify the exponents and then multiply

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Rita ran 2 km 30 m in a 10 km marathon. How much more distance she has to cover to finish the marathon?
vichka [17]

Answer:

7.970km

Step-by-step explanation:2km 30m=2000m+30m=2030m  (1km=1000m)

total distance is 10km which is 10000m.

10000m Minus 2030m equals 7970m so this give's us the answer of 7.97km (7.970km) Hope this helps!

4 0
2 years ago
Bob and Doug are both 100-meter sprinters. Bob's sprint time is normally distributed with a mean of 10.00 seconds and Doug's spr
alexdok [17]

Answer:

The standard deviation (σ) = 0.05

Step-by-step explanation:

The question is to find the standard deviation.

STEEP 1: FIND THE MEAN

(10+9.9) ÷ 2 = 9.95

STEP 2: SQUARE THE DIFFERENCE BETWEEN SPRINT TIME AND MEAN

10-9.95= 0.05

0.05^2 = 0.0025

9.9 - 9.95= -0.0025

-0.0025^2 = 0.0025

STEP 3: FIND THE VARIANCE

0.0025+0.0025= 0.005

0.005/2= 0.0025

STEP 4: FIND THE STANDARD DEVIATION (σ )

√variance

√0.0025 = 0.05

Therefore

σ = 0.05.

From the standard deviation, the percentage probability of the higher value to occurs is

0.05×100= 5%

That means Doug has 95%

And Bob has 5%

3 0
3 years ago
How would you solve y+1= -4x ? with a step by step solution
polet [3.4K]

Answer:

There are an infinite number of solutions.

Step-by-step explanation:

An equation with 2 unknowns give an infinite amount of solutions, here is just one of the many:

Let y= 3 ( y can be any number)

(3) + 1 = -4x

4 = -4x

x = -4/4

x= -1

(x;y) = (-1;3)

Generally x and y can be any number, just let x or y be any number, then find the other variable based on the value of the number u assumed.

3 0
3 years ago
A particle, initially at rest, moves along the x-axis such that its acceleration at time t > 0 is given by a(t) = 6cos(t). At
Rom4ik [11]

a. By the fundamental theorem of calculus, the velocity function is

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

The particle starts at rest, so v(0)=0, and we have

v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t

Then the position function is

x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du

with x(0)=6, so

x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t

b. The particle is at rest whenever v(t)=0; this happens for

6\sin t=0\implies \sin t=0\implies t=n\pi

where n is any integer.

3 0
3 years ago
Number 11!! I don’t understand it!! Can someone help please?? Thank you
Novay_Z [31]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
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