Ask question

Ask question

All categories

Nookie1986 [14]

3 years ago

13

The zurassic zoo charges $11 each for adult admissions and $4 each for each child. The total bill for the 138 people from a scho

ol trip was $839. How many adults and how many children went to the zoo?

1 answer:

LenaWriter [7]3 years ago

4 0

The number of adults = 41

The number of children = 97

Step-by-step explanation:

Let x be the number of adults and

y be the number of children

then according to the given conditions

$x+y = 138\ \ \ Eqn\ 1\\11x+4y = 839\ \ \ Eqn\ 2$

From equation 1:

x = 138-y

Putting in equation 2

$11(138-y)+4y = 839\\1518-11y+4y = 839\\1518 -7y = 839\\-7y = 839-1518\\-7y = -679\\$

Dividing both sides by -7

$\frac{-7y}{-7} = \frac{-679}{-7}\\y = 97$

Putting y = 97 in equation 1

$x+ 97 = 138\\x = 138-97\\x = 41$

Hence,

The number of adults = 41

The number of children = 97

Keywords: Linear equations variables

Learn more about linear equations at:

#LearnwithBrainly

You might be interested in

Show each step along the Way<br><br>Ur mom

LekaFEV [45]

2x+6 = 20
take 6 from both sides
2x = 14
divide by 2 on both sides
x = 7

8 0

2 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

Write the solution to the given inequality in interval notation.

Effectus [21]

Is the last one
(-Infinity, -3] U (-1, positive infinity)

7 0

3 years ago

Read 2 more answers

You are working on a proof. You know that A and B are on the perpendicular bisector of CD. What can you conclude? A) AC = BD B)

MatroZZZ [7]

You can only conclude that AC = AD

Its C

5 0

3 years ago

a submarine travels at an elevation of -75 3/4 ft relative to sea level then its elevation changes by - 16 3/8 what is the new e

slamgirl [31]

Answer:

$New = -92\frac{1}{8}$

Step-by-step explanation:

Given:

$x = -75\frac{3}{4}$ --- Position

$\triangle x = -16\frac{3}{8}$ --- Change

Required

Find the new position

The new position is calculated as:

$New = x + \triangle x$

$New = -75\frac{3}{4} - 16\frac{3}{8}$

$New = -75.75 - 16.375$

$New = -92.125$

$New = -92\frac{125}{1000}$

$New = -92\frac{1}{8}$

3 0

3 years ago