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3 years ago

how much would $400 be worth after 16 years , if it were invested at 3% interest compounded annually ?

2 answers:

7 0

Hello!

Judging on the question you have provided I have generated this equation to represent the situation 400(1.03^x) X being years.

To solve this equation you need to plug in 16 for X amount of years.
The new equation should look something like this 400(1.03^16)

Lastly solve!
The answer you get should be $641.88

Hope this helped!
-Blake

egoroff_w [7]3 years ago

6 0

The equation for interest is
'Initial amount (interest rate in decimal form) ^ times compounded EX: years'

your equation would be
400(1.03)^16

which equals 641.882576 (not rounded)

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The gas tank is 20% full. At $3.00 per gallon of gas, find the cost to fill the tank. (1 gal = 231 in.3)

rewona [7]

The correct question in the attached figure

we know that

to fill the tank is required--------> 100%-20%--------> 80%
if 20% of the gas tank is-----------------> 288.75 gal
80% --------------------------------------> X gal
X=80*288.75/20--------> X=1155 gal

if 1 gal----------------> cost $3
1155 gal----------> $X
X=1155*3--------> X=$3465

the answer is
the cost to fill the tank is $3465

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2 years ago

What is the answer for number 8 and pls give step by step

Pie

Answer:

Trapezoid 1 (left side):

Base 1 = 2

Base 2 = 5

Trapezoid 2 (right side):

Base 1 = 6

Base 2 = 8

Step-by-step explanation:

1st trapezoid:

b_1 = x

b_2 = x + 3

h = 4

Hence, area (from formula) would be:

$A=\frac{h}{2}(b_1+b_2)\\A=\frac{4}{2}(x+x+3)\\A=2(2x+3)\\A=4x+6$

2nd trapezoid:

b_1 = 3x

b_2 = 4x

h = 2

Putting into formula, we get:

$A=\frac{h}{2}(b_1+b_2)\\A=\frac{2}{2}(3x+4x)\\A=1(7x)\\A=7x$

Let's equate both equations for area and find x first:

$4x+6=7x\\6=7x-4x\\6=3x\\x=\frac{6}{3}\\x=2$

We can plug in 2 into x and find length of each base of each trapezoid.

Trapezoid 1 (left side):

Base 1 = x = 2

Base 2 = x + 3 = 2 + 3 = 5

Trapezoid 2 (right side):

Base 1 = 3x = 3(2) = 6

Base 2 = 4x = 4(2) = 8

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