Answer:
24
Step-by-step explanation:
Let's see the factor pairs of 60 first.
1,60
2,30
3,20
4,15
5,12
6,10
10,6
12,5
15,4
20,3
60,1
1,60 and 60,1 is not possible for xy1 and 1xy. It is because any one digit*one digit=not 60. The remaining pairs are...
2,30
3,20
4,15
5,12
6,10
10,6
12,5
15,4
20,3
30,2
Next, start with 2,30 and 30,2
The one digit factor pairs of 30 is 5 and 6.
So...
256 is possible
265 is possible
562 is possible
652 is possible
3,20
4,15
5,12
6,10
10,6
12,5
15,4
20,3
+4
Next, 3,20 and 20,3
20=4*5
453,543,345,354
4,15
5,12
6,10
10,6
12,5
15,4
+8
4,15 and 15,4
4 number that are possible(5*3=15)
5,12
6,10
10,6
12,5
+12
5,12 and 12,5
3,4 and 2,6
526,562,534,543,435,345,265,625
6,10
10,6
+20
10=5*2
+4
20+4=24
(Sorry it's long)
P(the students she selects are both boys)=7/12×5/10=35/120=7/24
Answer:
Never because one of them goes 1k8 and one of them goes 24 so if they that song every time then it would be the same time diffrence even if you try a million tinmes
Step-by-step explanation:
Given:
The two numbers are
To find:
The highest common factor (HCF) of A and B
Solution:
We have,
...(i)
All the factors of A are prime but the factors of B are not prime. So, it can be written as
...(ii)
From (i) and (ii), it is clear that 3 is the only common factor of A and B. So,
Therefore, the highest common factor (HCF) of A and B is 3.
Answer:
9.42
Step-by-step explanation:
