Answer:
0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches
Step-by-step explanation:
Mean trout length (μ) = 14 inches
Standard deviation (σ) = 3 inches
The z-score for any given trout length 'X' is defined as:
e interval
For a length of X =12 inches:

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.
For a length of X =18 inches:

According to a z-score table, a score of 1.333 is equivalent to the 90.88th percentile of the distribution.
The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

Answer:
15(b)
16(a)
Step-by-step explanation:
15) 2x+10/2
Taking 2 common
2(x+5)/2
x+5
16) -2(-x-3)
(-2*-x)+(-2*-3)
2x+(6)
2x+6
(step 1) (6a+5)(a-1)=0
(step 2) 6a+5=0 or a-1=0
answer is
a= -5/6 or a= 1
i hope this helps! ;)
So let's add variables according to the ratio:
3n + 2n = <span>£80
5n = </span><span>£80
n = 16
3(16):2(16)
48:32
Tom gets </span>£48, and Jerry gets <span>£32</span>