Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
Answer:
it is b i did it on eg 2020
Step-by-step explanation:
Answer:
n = 32
Step-by-step explanation:
<u><em>Given:</em></u>
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<u><em>Solve:</em></u>
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~![\mathrm{[Kavinsky]}](https://tex.z-dn.net/?f=%5Cmathrm%7B%5BKavinsky%5D%7D)
Answer: 66 degrees
Step-by-step explanation:
Sum of the angle measures is 180, so:
71 + x + 49 + x + 72 = 180
2x + 192 = 180
2x = -12
x = -6
Meaning the measure of angle A = -6 + 72 = 66 deg.