3 years ago

Hello, can you please help me I need to write an expression for this word problem

Mathematics

1 answer:

Fudgin [204]3 years ago

5 0

4•(-24)-3 You don't need any parenthesis because it's order of operations

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Use integration by parts to find the integrals in Exercise.<br> ∫(4x-12)e-8x dx.

stepladder [879]

Answer:

$e(2x^{2} -12x)-4x^{2}+C$

Step-by-step explanation:

We have been given an indefinite integral as $\int \left(4x-12\right)e-8x\:dx$ . We are asked to find the given integral.

Let us solve our given problem.

$\int \left(4x-12\right)e\:dx-\int 8x\:dx$

Take out constant:

$e\int \left(4x-12\right)\:dx-8\int x\:dx$

$e(\int 4x\:dx -\int 12\right\:dx)-8\int x\:dx$

$e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C$

$e(\frac{4x^{2}}{2} -12x)-8*\frac{x^{2}}{2}+C$

$e(2x^{2} -12x)-4x^{2}+C$

Therefore, our required integral would be $e(2x^{2} -12x)-4x^{2}+C$ .

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3 years ago

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The is going to be infinite answers

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7 cos x+1=6 secx solve for x

jonny [76]

7cos(x) + 1 = 6sec(x)
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cos(x) = 6/7 , x = arccos(6/7) and
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