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3 years ago

Which of the following equations are equivalent? Select three options.

Mathematics

1 answer:

sesenic [268]3 years ago

5 0

No matter how much life puts you down get back up and try again go with what your gut tells you. :) <3

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EASY I NEED HELP<br><br> MATH QUESTION

gayaneshka [121]

Answer:

Step-by-step explanation:

just put in 5 for x

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3 years ago

Use the Law of Cosines to find the specified missing value. Approximate your answer to the nearest tenth.

Charra [1.4K]

<h3>Answer: 176.6</h3>

Work Shown:

$b^2 = a^2 + c^2 - 2*a*c*\cos(B)\\\\b^2 = 150^2 + 30^2 - 2*150*30*\cos(150)\\\\b^2 \approx 31194.22863406\\\\b \approx \sqrt{31194.22863406}\\\\b \approx 176.618879608211\\\\b \approx 176.6\\\\$

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2 years ago

Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized.

Maksim231197 [3]

Answer:

............................

8 0

3 years ago

Read 2 more answers

Joes age (j) is half Martha’s (m). Combined, their age is 42. What are their ages?

svp [43]

Answer:

Joe is 14.

Martha is 28.

Step-by-step explanation:

Use the variables and information from the question to make equations.

If Joe's age is half Martha's:

(1/2)m = j OR 2j = m

If their ages combined is 42:

m + j = 42

We can substitute the equation m=2j into equation m + j = 42, replacing "m".

m + j = 42 Substitute m for 2j

2j + j = 42 Combine like terms, terms with same varables

3j = 42 Divide both sides by 3 to isolate j

j = 14 Joe's age

Since j = 14, we can substitute it into equation m=2j to find "m".

m = 2j Substitute j for 14

m = 2(14) Simplify

m = 28 Martha's age

Therefore Joe is 14 and Martha is 28.

5 0

4 years ago

The radius of circle A is three feet less than twice the diameter of circle B. If the sun mmm of the diameters of both circles i

yanalaym [24]

Answer:

Area of Circle A = 1133.54

Circumference of Circle A= 119.32

Step-by-step explanation:

Given: Sum of both circle diameters= 49 feet.

Circle A radius= Three feet less than twice the diameter of circle B.

Lets assume diameter of Circle B is "x"

∴ Circle A radius (r)= $(2x-3)$

We know, the diameter of circle is $2r$

Diameter of Circle A is $2\times (2x-3)$

Next as given sum of both circle diameter is 49 feet.

∴ $2(2x-3)+x= 49\ feet$

distributing 2 with 2x and -3

⇒ $4x-6+x= 49$

⇒ $5x-6= 49$

Adding both side by 6

⇒ $5x=55$

Cross multiplying both side.

⇒ $x=\frac{55}{5} = 11$

∴ Diameter of circle B is 11 feet.

Next, subtituting the value of x to get the value of radius for Circle A.

Radius of circle A= $(2x-3)$

⇒ Radius of circle A= $(2\times 11-3)= 22-3$

∴ Radius of circle A= 19 feet.

Area of circle= $\pi r^{2}$

Taking π= 3.14

Area of circle A= $3.14\times 19^{2} = 3.14\times 361$

∴ Area of circle A= 1133.54

Circumference of circle= 2πr

Circumference of Circle A= $2\times 3.14\times 19= 119.32$

∴ Circumference of Circle A= 119.32

3 0

3 years ago

Read 2 more answers