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Rufina [12.5K]
3 years ago
10

Is this answer correct?

Mathematics
1 answer:
Sav [38]3 years ago
6 0

Answer:yes

Step-by-step explanation:

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A ball of radius 11 has a round hole of radius 5
inn [45]

Answer:

3,847.40376

Step-by-step explanation:

Volume of a sphere=

4/3π(11)³=5,575.27976

Volume of a cylinder=

π(5)²(22)=1,727.876

Total volume=

5,575.27976-1,727.876=3,847.40376

3 0
4 years ago
Which of the following are polynomials?<br><br> PLS HELP
Arturiano [62]

Answer:

option (B) I'm certain of.

but if you are required to choose more than one then option (B) and (C) since polynomials are coefficients with power 2.

Step-by-step explanation:

Hope this helps.

Good luck.

4 0
2 years ago
I need to know what is the chance the driver still got in an accident
Yakvenalex [24]

Answer:

answer is 35

Step-by-step explanation:

5 0
3 years ago
Hotels’ use of ecolabels. Refer to the Journal of Vacation Marketing (January 2016) study of travelers’ familiarity with ecolabe
Alexxx [7]

Answer:

a) 0.7486; b) 0.6518; c) No

Step-by-step explanation:

We use z scores to answer these questions.  The formula for a z score is

z=\frac{X-\mu}{\sigma}

Our mean, μ, is 44; our standard deviation, σ, is 1.5.

For part a,

We want P(X > 43):

z = (43-44)/1.5 = -1/1.5 = -0.67

Using a z table, we see that the area under the curve to the left of this is 0.2514.  However, we want the area to the right; this means we subtract from 1:

1 - 0.2514 = 0.7486

For part b,

We want P(42 ≤ X ≤ 45):

z = (42-44)/1.5 = -2/1.5 = -1.3

z = (45-44)/1.5 = 1/1.5 = 0.67

Using a z table, the area under the curve to the left of z = -1.3 is 0.0968.  The area under the curve to the left of z = 0.67 is 0.7486.

The area between them is 0.7486 - 0.0968 = 0.6518.

For part c,

A response of 35 has a z score of

z = (35-44)/1.5 = -9/1.5 = -6

This is 6 standard deviations below the mean.  This is more than the amount required to make this an outlier, or an unlikely response.

8 0
4 years ago
How do you know where to put the constant when finding general solutions for differential equations?
Norma-Jean [14]
Let's suppose we want to solve y'=y with y(0)=2. Separating variables and integrating, we get

\displaystyle\int\dfrac{\mathrm dy}y=\int\mathrm dx\implies\ln|y|=x+C\implies y=e^{x+C}

Leaving the solution in this form, the initial condition gives

2=e^{0+C}=e^C\implies C=\ln2

This means the solution is y=e^{x+\ln2}.

Now if we were to write y=e^{x+C}=e^xe^C=Ce^x, then we would have found

2=Ce^0\implies C=2

so that the solution would have been y=2e^x.

But these two solutions are the same, since y=e^{x+\ln2}=e^xe^{\ln2}=2e^x. So we get the same solution regardless of where we place C, despite getting different values for C.
5 0
3 years ago
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