Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
You can write this ratio in two other ways:
7 to 13
7 : 13
I think it’s AC, but I may be wrong
The answer is D. 2x - 4/x^2- 4
Answer:
Allison worked 6 hours lifeguarding and 3 hours washing cars.
Step-by-step explanation:
Let
Number of hours Allison worked lifeguarding last week = x
Number of hours Allison worked washing cars last week = y
1. Last week Allison worked 3 more hours lifeguarding than hours washing cars hours, then

<u>Lifeguarding:</u>
$12 per hour
$12x in x hours.
<u>Washing cars:</u>
$8 pere hour
$8y in y hours.
2. Allison earned a total of $96, hence

You get the system of two equations:

Plot the graphs of these two equations (see attached diagram). These line intersect at point (6,3), so Allison worked 6 hours lifeguarding and 3 hours washing cars.