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andreyandreev [35.5K]
3 years ago
7

A jar contains 11 pennies and 8 dimes. What is the ratio of dimes to pennies?

Mathematics
2 answers:
Galina-37 [17]3 years ago
6 0
I hope this helps you




dimes = 8


pennies = 11



8:11
Trava [24]3 years ago
3 0
Dimes to pennies = 8 to 11
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Answer:

The answer would be letter J

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3 years ago
The mean resting pulse rate for men is 72 beats per minute. A simple random sample of men who regularly work out at Mitch's Gym
BARSIC [14]

Answer:

We conclude that the mean resting pulse rate for men is 72 beats per minute.

Step-by-step explanation:

We are given that he mean resting pulse rate for men is 72 beats per minute. Assume that the standard deviation of the resting pulse rates of all men who work out at Mitch's Gym is known to be 2.6 beats per minute.

A simple random sample of men who regularly work out at Mitch's Gym is obtained and their resting pulse rates (in beats per minute) are listed below;

87, 89, 69, 63, 70, 65, 88, 84, 58, 53, 66, 70.

Let \mu = <u><em>mean resting pulse rate for men.</em></u>

SO, Null Hypothesis, H_0 : \mu = 72 beats/minute     {means that the mean resting pulse rate for men is 72 beats per minute}

Alternate Hypothesis, H_A : \mu < 72 beats/minute      {means that the mean resting pulse rate for men is less than 72 beats per minute}

The test statistics that would be used here <u>One-sample z-test statistics</u> as we know about population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean mean resting pulse rate = \frac{\sum X}{n}

                =  \frac{87+ 89+ 69 +63 +70 +65+ 88+ 84+ 58+ 53+ 66+ 70}{12}  = 71.83 beats/minute

            \sigma = population standard deviation = 2.6 beats per minute

            n = sample of men = 12

So, <u><em>the test statistics</em></u>  =  \frac{71.83 - 72}{\frac{2.6}{\sqrt{12} } }    

                                     =  -0.23

The value of z test statistics is -0.23.

<u></u>

<u>Also, P-value of the test statistics is given by;</u>

            P(Z < -0.23) = 1 - P(Z \leq 0.23)

                                 = 1 - 0.59095 = <u>0.40905</u>

Now, at 0.05 significance level the z table gives critical value of -1.645 for left-tailed test.

Since our test statistic is more than the critical value of z as -0.23 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that the mean resting pulse rate for men is 72 beats per minute.

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3 years ago
How to solve G(2x-3)= (2x-3+a)-(2x-3+a)
madreJ [45]

Given f (x) = 2x, g(x) = x + 4, and h(x) = 5 – x3, find (f + g)(2), (h – g)(2), (f × h)(2),


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3 years ago
Given f (x) = -12x + 72, find x when f(x) = 24.
Neko [114]

Answer:

x = 4

Given:

f(x) = -12x + 72

f(x) = 24

Step-by-step explanation:

=  >  - 12x + 72 = 24 \\  \\  =  >  - 12x = 24 - 72 \\  \\  =  >   \cancel{- }12x =   \cancel{-} 48 \\  \\  =  > 12x = 48 \\  \\  =  > x =  \frac{48}{12}  \\  \\  =  > x = 4

4 0
3 years ago
5. Two similar figures have volumes 27 in.? and 125 in.?. The surface area of the smaller figure is 63 in.. (1 point)
GREYUIT [131]

Answer:

175\ in^{2}

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the larger solid

y----> volume of the smaller solid

z^{3}=\frac{x}{y}

we have

x=125\ in^{3}

y=27\ in^{3}

substitute

z^{3}=\frac{125}{27}

z=\frac{5}{3}

step 2

Find the surface area of the larger solid

we know that

If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared

Let

z----> the scale factor

x----> surface area of the larger solid

y----> surface area of the smaller solid

z^{2}=\frac{x}{y}

we have

z=\frac{5}{3}

y=63\ in^{2}

substitute

(\frac{5}{3})^{2}=\frac{x}{63}

x=\frac{25}{9}*63=175\ in^{2}

3 0
3 years ago
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