Mitosis produces two diploid (2n) somatic cells that are genetically identical to each other and the original parent cell, whereas meiosis produces four haploid (n) gametes that are genetically unique from each other and the original parent (germ) cell.
Answer:
Clues that can be used to determine whether the movement of solutes through the membrane is passive or active could be the molecule size, membrane potential, and the presence/absence of membrane protein.
Explanation:
Solutes transport through the cellular membrane depends on the solute size, membrane potential, and the presence/absence of integral membrane protein.
There are two types of transport: Active and passive.
- Passive transport: It does <u>not need energy</u>; it is driven by a chemical potential gradient. <u>Small molecules</u> with no charge are transported through the membrane in a gradient favor, from a high concentration region to a low concentration region. There are two types of passive transport: <em>By simple diffusion</em> (small molecules pass through the membrane by themselves) and by <em>facilitated diffusion</em> (molecules are helped by integral membrane proteins to pass through the membrane). In facilitated diffusion, the helping protein can be a <u>channel protein</u> (hydrophilic pores that allow the molecule to pass with no interaction) or a <u>carrier protein</u> (proteins with mobile parts that suffer modification as the molecule pass to the other side).
- Active transport: It <u>does need ATP energy</u> to pass the molecule through the membrane, as they have to <u>move against the electrochemical gradient</u>. This kind of transport is always mediated by a <u>carrier protein</u>. These proteins join with the molecules and suffer changes as they pass the solute to the other side of the membrane. An important example of this kind of transport is the sodium-potassium bomb.
I
can conclude that if the color of the solution in the control changed, the
control enabled me to have a perspective in which there is no change ought to
have happened. On the off chance that the control arrangement changed its
color, I would conclude that there were life forms in the water.
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Answer:
See the answer below
Explanation:
<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>
Mathematically,
molarity x number of moles before dilution = molarity x number of moles after dilution.
For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM
Applying the equation:
10 x initial volume = 3 x 2
initial volume = 6/10 = 0.6
<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and 1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>
For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM
10 x initial volume = 8 x 2
initial volume = 16/10 = 1.6
<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>
