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Alika [10]
3 years ago
11

Those that work in the Printing Technology pathway are typically self-employed, and work indoors. self-employed, and work outdoo

rs. not self-employed, and work outdoors. not self-employed, and work indoors.
Computers and Technology
2 answers:
Maurinko [17]3 years ago
8 0

From all the possible options to answer the question given, it is apparent that the best description of working situation for someone who works in the Printing Technology pathway would be (A) self-employed and work indoors.

It is clear that someone who works in Printing Technology would work indoor since they would predominantly be using computers and printer machines. It is also likely that they would be self-employed.

Reika [66]3 years ago
3 0
A.) Those that work in the Printing Technology pathway are typically "<span>self-employed, and work indoors"

Hope this helps!</span>
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How would you describe the difference between a syntax error and a logic error?
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Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
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Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

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Answer:

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Explanation:

what do you mean by that

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