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Serhud [2]
3 years ago
15

Complete the method, print Multiples(), that takes in a positive integer n, and another positive integer, max. Print out all the

multiples of n that are less than or equal to max. Print each multiple on a separate line. For example, if the method is called with n
Computers and Technology
1 answer:
musickatia [10]3 years ago
3 0

Answer:

public static void printMultiples(int n, int max){

    for (int i=1; i<=max; i++){

        if(i%n == 0)

            System.out.println(i);

    }

}

Explanation:

Create a method called printMultiples that takes two parameters n and max

Inside the method, create a for loop that iterates from 1 to max. If i, a number between 1 and max, % n is equal to 0, that means the number is a multiple of n, print the number.

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Which of the following lines correctly defines a String variable
lidiya [134]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is C i.e. String s = "apluse";

The rule or syntax of declaring string in any programming language is given below:

String variable-name = "yourString";

For declaring string variable, first, you write "String" that is a keyword of a programming languages for declaring string variables, such as int before the variable name for declaring integer variable. Then, you need to write a meaningful name of the string as a variable. After string variable name, you need to put the equal operator and then write the string in double quotation("") marks and after that put the instruction terminator that is ";".

So, according to this syntax, option C is correct.

While other options are not correct because:

In option a, string is not encapsulated in double quotation. Option B does not have varaible type such as String and Option E does not have variable name and its value also. So, only option C is correct and all other except C are incorrect.

3 0
3 years ago
While using a Web-based order form, an attacker enters an unusually large value in the Quantity field. The value she entered is
maxonik [38]

Answer: integer overflow

Explanation:

The type of attack has occurred in this scenario is a integer overflow. An integer overflow occurs when there's an attempt by an arithmetic operation to create a numeric value which is outside the range which the given numbers are able to represent.

In this, the integer overflow occurs when the result of the integer operation cannot be able to fit in the allocated memory space which then brings about an unexpected result.

6 0
3 years ago
Write a function named power that accepts two parameters containing integer values (x and n, in that order) and recursively calc
lianna [129]

Answer:

Following are the code to the given question:

int power(int x, int n)//defining a method power that accepts two integer parameters

{

if (n == 0)//defining if block to check n equal to 0

{

return 1; //return value 1

}

else//defining else block

{

x = x * power(x, --n); //use x variable to call method recursively

}

return x; //return x value

}

Explanation:

In the above-given code, a method power is defined that accepts two integer variable in its parameter, in the method a conditional statement is used which can be defined as follows:

  • In the if block, it checks "n" value, which is equal to 0. if the condition is true it will return value 1.
  • In the else block, an integer variable x is defined that calls the method recursively and return x value.
8 0
3 years ago
In the bussiness cycle which term best fits the labeled point on the graph
andrew11 [14]
In the business cycle, the term that best fits the labeled point on the graph of Production output vs Time is Contraction
8 0
2 years ago
Create two functions (with appropriate names) that produce the output below. Both functions must use a prototype. All that shoul
Mariulka [41]

Answer:

In C++:

#include <iostream>

using namespace std;

void function1(); void function2();

int main(){

   function1();    function2();

   return 0;}

void function1(){

   cout<<"This is the first part of my program."<<endl<<"It was created with a function"<<endl;}

void function2(){

   cout<<"This is the second part of my program."<<endl<<"It was created with a different function.";}

Explanation:

This defines the function prototypes

void function1(); void function2();

The main begins here

int main(){

This calls the two functions from main

   function1();    function2();

   return 0;}

This calls function1()

<em>void function1(){</em>

<em>    cout<<"This is the first part of my program."<<endl<<"It was created with a function"<<endl;}</em>

This calls function2()

<em>void function2(){</em>

<em>    cout<<"This is the second part of my program."<<endl<<"It was created with a different function.";}</em>

3 0
3 years ago
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