<h2>Answer:</h2><h2>Releases a new video of its new high - tech manufacturing facility; To create a customer alert about a new program. </h2>

<h2>2)Hosts an online sweepstakes. .....;To increase brand loyalty </h2>

<h2>3)Gives bloggers.....:To give customers a peek into its operation.</h2>

<h2>4)Asks customers to determine their. .....;To allow customers to be part of the product development. </h2>

8 0

3 years ago

Write the code in python to ask the user to input two integers. Your program will then print the greatest common divisor of the

Hunter-Best [27]

import math

num1 = int(input("Enter a number: "))

num2 = int(input("Enter a number: "))

print(math.gcd(num1, num2))

The gcd() - greatest common divisor function, which is part of the math module works perfectly in this situation.

3 0

3 years ago

Does anybody know the answer to 5.7.5: Factorial of Code HS? I can’t figure it out

shutvik [7]

function myFunction(num){

n = 0;

total = 1;

while (n < num){

total *= (num - n);

n+=1;

}

return total;

}

alert(myFunction(6));

I'm not too proficient in JavaScript but here's what the function would look like. I hope this helps!

4 0

2 years ago

Read 2 more answers

Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs

marishachu [46]

Answer:

public static String bothStart(String text1, String text2){
String s = "";
if(text1.length() > text2.length()) {
for (int i = 0; i < text2.length(); i++) {
if (text1.charAt(i) == text2.charAt(i)) {
s += text1.charAt(i);
}else{
break;
}
}
return s;
}else{
for (int i = 0; i < text1.length(); i++) {
if (text1.charAt(i) == text2.charAt(i)) {
s += text1.charAt(i);
}else{
break;
}
}
return s;
}
}

Explanation:

Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).

<em />

Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>

<em />

At the end, return the s as output (Line 21).

5 0

3 years ago