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Goryan [66]
3 years ago
10

IF the area of the frame was 64inches², what would be 2 possible sets of dimensions that could be used to make a frame with that

area? Set 1: Set 2: Explain your thinking:
Mathematics
1 answer:
zheka24 [161]3 years ago
3 0
Set 1.) Using the formula of the area of square:
                 A = a^2; where a = side
64 inches^2 = 8^2 inches^2
64 inches^2 = 64 inches^2

Set 2.) Using the formula of the are of rectangle:
                 A = L * W; where L = length; W = width
64 inches^2 = 16 inches * 4 inches
64 inches^2 = 64 inches^2

Therefore, the possible dimensions of the frame are:
8x8 ; 16x4
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Answer:

k =1

Step-by-step explanation:

Solve for k:

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Expand out terms of the right hand side:

0.5 k + 2.5 = 2 k + 1

Subtract 2 k from both sides:

(0.5 k - 2 k) + 2.5 = (2 k - 2 k) + 1

0.5 k - 2 k = -1.5 k:

-1.5 k + 2.5 = (2 k - 2 k) + 1

2 k - 2 k = 0:

2.5 - 1.5 k = 1

Subtract 2.5` from both sides:

(2.5 - 2.5) - 1.5 k = 1 - 2.5

2.5 - 2.5 = 0:

-1.5 k = 1 - 2.5

1 - 2.5 = -1.5:

-1.5 k = -1.5

Divide both sides of -1.5 k = -1.5 by -1.5:

(-1.5 k)/(-1.5) = (-1.5)/(-1.5)

(-1.5)/(-1.5) = 1:

k = (-1.5)/(-1.5)

(-1.5)/(-1.5) = 1:

Answer:  k = 1

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Step-by-step explanation:

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Hope it helps ⚜

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