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Goryan [66]
3 years ago
10

IF the area of the frame was 64inches², what would be 2 possible sets of dimensions that could be used to make a frame with that

area? Set 1: Set 2: Explain your thinking:
Mathematics
1 answer:
zheka24 [161]3 years ago
3 0
Set 1.) Using the formula of the area of square:
                 A = a^2; where a = side
64 inches^2 = 8^2 inches^2
64 inches^2 = 64 inches^2

Set 2.) Using the formula of the are of rectangle:
                 A = L * W; where L = length; W = width
64 inches^2 = 16 inches * 4 inches
64 inches^2 = 64 inches^2

Therefore, the possible dimensions of the frame are:
8x8 ; 16x4
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Answer:

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This is a probablity question

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MATH HELP PLEASE
Anuta_ua [19.1K]

calculate the slopes of the lines using the gradient formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

(x₁, y₁ ) = A(- 4, - 1) and (x₂, y₂ ) = B(-1, 2 )

m_{AB} = \frac{2+1}{-1+4} = \frac{3}{3} = 1

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(x₁, y₁) = C(5, 1 ) and (x₂, y₂ ) = D(1, - 3)

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m_{AD} = \frac{-3+1}{1+4} = - \frac{2}{5}

Quadrilateral ABCD is not a parallelogram since only one pair of opposite sides is parallel , that is AB and CD



6 0
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