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2 years ago

Pls help fast i will mark brainlyiest

Mathematics

1 answer:

Leona [35]2 years ago

5 0

The mean temperature of the orange juice is 5 °F <u>greater than</u> the mean temperature of the water

<h3>Calculating Average</h3>

From the question, we are to calculate how much greater the mean temperature of the orange juice is than the mean temperature of the water

From the given chart,

Mean temperature of orange juice = $\frac{59+65+72+78+85+81}{6}$

Mean temperature of orange juice = $\frac{440}{6}$

Mean temperature of orange juice = 73.33 °F

Mean temperature of water = $\frac{55+62+68+71+79+75}{6}$

Mean temperature of water = $\frac{410}{6}$

Mean temperature of water = 68.33 °F

Difference in temperature = 73.33 °F - 68.33 °F

Difference in temperature = 5 °F

Hence, the mean temperature of the orange juice is 5 °F <u>greater than</u> the mean temperature of the water

Learn more on Calculating average here: brainly.com/question/17102414

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Answer:

Therefore, the first polynomial is:

$Z=\frac{1}{2}x^2+\frac{1}{2}\\$

the second polynomial is:

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Step-by-step explanation:

We assume that: Z is first polynomial and Y is second polynomial.

Therefore, we have

$Z+Y=x^2\\\\Z-Y=1\\\\\implies Z+Y+Z-Y=x^2+1\\\\2Z=x^2+1\\\\Z=\frac{1}{2}x^2+\frac{1}{2}\\$

now, we get

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the second polynomial is:

$Y=\frac{1}{2}x^2-\frac{1}{2}\\$

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