Answer:
10 hours lifeguarding, 6 hours tutoring
Step-by-step explanation:
As you know how long he worked and how much he earned, it's worth seeing how many hours it would have been had he worked just tutoring or just lifeguarding.
$242 / 11 = 22 hours if it was just lifeguarding
$242 / 22 = 11 hours (as it's exactly double the wage) if it was just tutoring
We now know that he worked some combination of both
Calculating his average wage can help work out which he worked more of:
$242 / 16 = 15.125
That means Parker's average hourly wage was 15.125 which is closer to 11 than 22 (16.50 would mean an exactly even split between the two) so he did more hours lifeguarding than tutoring so more than 8 hours.
What I then do is consider the variations that could work:
9 (lifeguarding) and 7 (tutoring) = 99 + 154 = 243
So we're almost exactly there straight away, but not quite so...
10 and 6 = 110 + 132 = 242
There you have it.
Answer: FALSE.
Step-by-step explanation:
Given the following equation provided in the exercise:
You need to solve for the variable "x".
In order to solve for "x" you can folllow the steps shown below:
1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:
2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:
Therefore, as you can observe, the given equation has no solutions.
This is what the graph of your equation looks like. It is a linear equation
The answer is F=40, when a=10.
Divide 28 by 7, so F=4, when A=1. Then multiply 4 by 10 and you get F=40.
