Lets first reduce 12/20....12/20 = 3/5
5/3 + 3/5 = 25/15 + 9/15 = 34/15 or 2 4/15
Answer:
h ≈ 6
Step-by-step explanation:
Using the formula:
Or: ![V = \pi r^{2} \frac{h}{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20r%5E%7B2%7D%20%5Cfrac%7Bh%7D%7B3%7D)
We can rearrange to make h the formula:
h= 3 (64/3.14×3.2²)
h = 3(64/3.14×10.24)
h=3(64/32.1536)
h=3(1.99044585987)
h= 5.97133757962
h ≈ 6
Answer:
<h2>
![\sqrt{30}](https://tex.z-dn.net/?f=%20%5Csqrt%7B30%7D%20)
</h2>
Step-by-step explanation:
Given,
Perpendicular ( p ) = 3√2
Base ( b ) = 2√3
Hypotenuse ( h ) = ?
Now, let's find the length of the hypotenuse:
Using Pythagoras theorem:
![{h}^{2} = {p}^{2} + {b}^{2}](https://tex.z-dn.net/?f=%20%7Bh%7D%5E%7B2%7D%20%20%3D%20%20%7Bp%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%20)
plug the values
![{h}^{2} = {(3 \sqrt{2} )}^{2} + {(2 \sqrt{3} )}^{2}](https://tex.z-dn.net/?f=%20%7Bh%7D%5E%7B2%7D%20%20%3D%20%20%7B%283%20%5Csqrt%7B2%7D%20%29%7D%5E%7B2%7D%20%20%2B%20%20%7B%282%20%5Csqrt%7B3%7D%20%29%7D%5E%7B2%7D%20)
To raise a product to a power, raise each factor to that power
![{h}^{2} = 9 \times 2 + 4 \times 3](https://tex.z-dn.net/?f=%20%7Bh%7D%5E%7B2%7D%20%20%3D%209%20%5Ctimes%202%20%2B%204%20%5Ctimes%203)
Multiply the numbers
![{h}^{2} = 18 + 12](https://tex.z-dn.net/?f=%20%7Bh%7D%5E%7B2%7D%20%20%3D%2018%20%2B%2012)
Add the numbers
![{h }^{2} = 30](https://tex.z-dn.net/?f=%20%7Bh%20%7D%5E%7B2%7D%20%20%3D%2030)
Take the square root of both sides of the equation
![h = \sqrt{30}](https://tex.z-dn.net/?f=h%20%3D%20%20%5Csqrt%7B30%7D%20)
Hope this helps...
Best regards!!
Answer:
5
Step-by-step explanation:
its number 5 I learned this before
Answer:
YESSSSSSS
Step-by-step explanation: