Answer:
Step-by-step explanation:
Given the following coordinates of a triangle
P(-10,1)
Q(-10,-7)
R(-5,-7)
Required
Length of PQ
PQ = √(y2-y1)²+(x2-x1)²
From the coordinate;
x1 = -10, y1 = 1, x2 = -10 y2 = -7
Substitute
PQ = √(-7-1)²+(-10-(-10))²
PQ = √(-8)²+0²
PQ = √64
PQ = 8units
Hence the length of PQ in units is 8units
Answer:
m<1=134
m<2=46
x=13
Step-by-step explanation:
Angle 2 can be set equal to 180 since the angle is supplementary after transferring angle 2 to its alternate interior.
4x-6+10x+4=180
Combine like terms
14x-2=180
Solve for x
14x=182
x=13
Now plug x in for the two angles
10(13)+4
130+4
m<1=134
4(13)-6
52-6
m<2=46
134+46=180, verified
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Answer:
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