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katovenus [111]
3 years ago
6

ΔABC is a right triangle in which is a right angle, AB = 1, AC = 2, and BC = .

Mathematics
1 answer:
ollegr [7]3 years ago
8 0
We are asked to solve for the measurement of side BC in the given right triangle ΔABC and other side measurements were also given such as AB=1 and AC = 2. Since this is a right triangle, we can use and apply the Pythagorean theorem c²= a² + b² and the solution is shown below:
c = AC
b = BC
a = AB
AC² = AB² + BC² , substitute values we have:
2² = 1² + BC²
BC² = 4-1
BC = √3
BC = 1.732

The answer for the length of BC is 1.732 units.
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Answer:

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Step-by-step explanation:

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branliest if it is helpful

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Bad White [126]

Answer:

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Step-by-step explanation:

we are given that

\displaystyle P =  \left(x,  - \frac{  \sqrt{7} }{4}  \right)

we want to figure out x

remember that,

In <u>unit</u><u> </u><u>circle</u> x coordinate is considered cos and y coordinate is considered sin

so in order to figure out x we should figure out the value of <u>cos</u> to do we can consider <u>Pythagoras</u><u> trig</u><u> </u><u>indentity</u>

given by

\displaystyle  \sin ^{2} ( \theta)  +  {  \cos}^{2} ( \theta) = 1

we are given sin=-√7/4 thus

substitute:

\displaystyle   \left( - \frac{ \sqrt{7}  }{4}  \right) ^{2}   +  {  \cos}^{2} ( \theta) = 1

simplify square:

\displaystyle  \frac{7}{16}  +  \cos ^{2} ( \theta)  = 1

move left hand side expression to right hand side and change its sign:

\displaystyle   \cos ^{2} ( \theta)  = 1 -  \frac{7}{16}

simplify Substraction:

\displaystyle   \cos ^{2} ( \theta)  =  \frac{9}{16}

square root both sides:

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since in unit circle cos is x and P belongs to Q:IV negative cos isn't applicable

hence,

\displaystyle   x =   \frac{3}{4}

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Answer:

Step-by-step explanation:

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SashulF [63]

Answer:

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Step-by-step explanation:

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