What is the first step in solving quadraric equations by finding square roots??

How many liters of water must be added to 15 liters of 40 % sugar syrup to obtain 30 % sugar syrup?

faltersainse [42]

5 liters of water must be added.

Step-by-step explanation:

In this question form and equate equations for the amount of sugar in both syrups which does not change.

Let the amount of water to be added to 15 liters of 40% sugar syrup to be w liters

The 40% sugar syrup will contain 15 liters of 40% sugar syrup. This means that the amount of sugar contained in the syrup is 15 *0.4 = 6 liters......(i)

So for a 30% sugar syrup, the amount of syrup is =15 +w *L , thus amount of sugar in this syrup will be : (15+w)0.3*L--------(ii)

Because only water was added, the amount of sugar remains the same hence equate the equations for amount of sugar;

0.3(15+w)=6

solve for value of w as

4.5+0.3 w =6

0.3 w = 6-4.5

0.3 w = 1.5

w= 1.5/0.3 = 5 liters

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Mixtures :brainly.com/question/14587611

Keywords : liters, water , added, sugar syrup

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4 0

3 years ago

Bob nailed wooden board sections to a fence. He nailed 2/9 of a section in 1/10 hour. Explain how to use the information in the

jok3333 [9.3K]

Your fractions are your units and rates.

A "section" is a unit and 2 of 9 sections is a rate.
An hour is a unit and 1 of 10 hours is a rate.

You can multiply the fractions and create a new unit rate that would measure a section per hour.
I hope this helps.

4 0

3 years ago

Does anyone know how to solve this?

MrRissso [65]

9514 1404 393

Answer:

Step-by-step explanation:

The tangent of the angle can be found using the identity for the tangent of the difference of angles.

tan(α-β) = (tan(α) -tan(β))/(1 +tan(α)tan(β))

The tangent of the angle of each vector is the ratio of the j coefficient to the i coefficient.

tan(α) = -2/3

tan(β) = 4/7

tan(α-β) = (-2/3 -4/7)/(1 +(-2/3)(4/7))

= (-14-12)/(21 -8) = -26/13 = -2

Then the magnitude of the angle between the vectors is ...

arctan(2) ≈ 63.43°

5 0

3 years ago

In a polynomials equation do you add the exponents if they are different

Alexus [3.1K]

You can only add exponents if you are multiplying two of the same variable together. For example,
$x^{12} \times x^4 = x^{16}$

You take them away if you are dividing.
 $x^{12} \div x^4 = x^{8}$

In a polynomial equation, you can add together two of the same variable if they have the same exponent
 $3x^4 + 7x^4 = 10x^4$

Or you can take them away in a similar fashion,
 $3x^4 - 7x^4 = -4x^4$

But you cannot add two (or more) different exponents,
 $6+4x+7x^2 = 6+4x+7x^2$ (it does not get any simpler)

I hope this has answered your question, if not, leave a comment and I'll update the answer.

4 0

4 years ago

ok this is very long but the points are worth it PLS HELP I BEG!! like cmon its 50 points (i think..... i put 100)

ivanzaharov [21]

Answer:

Below!

Step-by step solution:

Dividing Mixed Numbers (Answers):

1. 2 9/10 ÷ 3 2/5

=> 29/10 ÷ 17/5
=> 29/10 x 5/17
=> 29/2 x 1/17
=> 29/34

2. 4 1/2 ÷ 3 1/5

=> 9/2 ÷ 16/5
=> 9/2 x 5/16
=> 45/32

3. 4 1/4 ÷ 3 4/5

=> 17/4 ÷ 19/5
=> 17/4 x 5/19
=> 85/76

4. 4 1/2 ÷ 2 2/5

=> 9/2 ÷ 12/5
=> 9/2 x 5/12
=> 3/2 x 5/4
=> 15/8

5. 3 1/2 ÷ 4 2/5

=> 7/2 ÷ 22/5
=> 7/2 x 5/22
=> 35/44

6. 4 3/5 ÷ 3 1/2

=> 23/5 ÷ 7/2
=> 23/5 x 2/7
=> 46/35

Dividing Fractions and Whole Numbers (Answers):

1. 10 ÷ 5/10

=> 10 x 10/5
=> 100/5
=> 20

2. 2/3 ÷ 7

=> 2/3 x 1/7
=> 2/21

3. 10 ÷ 2/4

=> 10 x 4/2
=> 10 x 2
=> 20

4. 10 ÷ 2/3

=> 10 x 3/2
=> 5 x 3
=> 15

5. 2/3 ÷ 3

=> 2/3 x 1/3
=> 2/9

6. 1/2 ÷ 7

=> 1/2 x 1/7
=> 1/14

Dividing Fractions (Answers):

1. 1/2 ÷ 1/3

=> 1/2 x 3
=> 3/2

2. 4/5 ÷ 1/2

=> 4/5 x 2
=> 8/5

3. 2/4 ÷ 7/10

=> 1/2 x 10/7
=> 5/7

4. 1/2 ÷ 5/10

=> 1/2 x 10/5
=> 1/2 x 2
=> 1

5. 2/4 ÷ 2/5

=> 2/4 x 5/2
=> 1/4 x 5/1
=> 5/4

6. 4/5 ÷ 1/3

=> 4/5 x 3
=> 12/5

Hoped this helped.

$BrainiacUser1357$

7 0

2 years ago

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