1.03=b this makes sense because it increases 3 percent so you add 1 to .03
Answer:Given expression : a(x-y)-b(x-y)
Now, (x-y) is common in both terms.
First factor is (x-y).
∴a(x−y)−b(x−y)=(x−y)(a−b)
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Good luck
We have that
<span>A' (2,1)
C(-2,2)-------> </span>Using the transformation-----> C' (-2+2,2+1)----> C' (0,3)
with
A' (2,1) and C' (0,3)
find the distance <span>C'A'
d=</span>√[(y2-y1)²+(x2-x1)²]----> d=√[(3-1)²+(0-2)²]----> d=√8----> 2√2 units
the answer is
the distance C'A' is 2√2 units
