H1 (t) = 196 - 16 t-squared. / / / H2 (t) = 271-16t-squared. / / / In each function, 't' is the number of seconds after that ball is dropped. / / / Each function is only true until the first time that H=0, that is, until the first bounce. Each function becomes very complicated after that, and we would need more information in order to write it.
Answer:
Step-by-step explanation:
You can use the definition:

Then if

we have

Then the derivative is

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).
Use the point-slope formula to get the equation of the tangent line:
<em>y</em> - (-2) = 3 (<em>x</em> - 0)
<em>y</em> + 2 = 3<em>x</em>
<em>y</em> = 3<em>x</em> - 2
Answer:
Step-by-step explanation:
1.89/14= .135
estimating to the nearest cent would be .14
3x + 20 = 5x - 16
3x - 5x = -16 - 20
-2x = -36
x = -36/-2
x = 18
The measure of angle xyz can also be said to be the measure of angle y.
So, y = (3•18 + 20)
y = 54 + 20
y = 74°
The measure of angle xyz = 74°.