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OLga [1]
3 years ago
10

If A = James's present age, write an expression for his age seven years from now.

Mathematics
1 answer:
ehidna [41]3 years ago
3 0
<span>If A = James's present age
then
</span><span>his age seven years from now = A - 7

hope it helps</span>
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What is the first step when solving the following inequality x+2/-5&lt;4? Group of answer choices A. Add 5 to both sides and DO
LiRa [457]

Assuming we're dealing with \frac{x+2}{-5} < 4, which is the same as writing (x+2)/(-5) < 4, then the answer is choice C.

We multiply both sides by -5 and this will flip the inequality sign.

-------------------------------------

Multiplying or dividing both sides by a negative number flips the inequality sign.

An example would be saying -2x < 10 leads to x > -5

What we can do is divide both sides by -2 and flip the inequality sign, or we could follow the steps shown below

  • -2x < 10
  • 0 < 10+2x ... adding 2x to both sides
  • -10 < 2x ... subtracting 10 from both sides; this is one way to see why the sign flip happens
  • 2x > -10
  • x > -10/2 ..... dividing both sides by 2
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3 years ago
If x is the first of two consecutive integers, express the sum of the two integers in terms of x
makkiz [27]

Answer:

2x+1

Step-by-step explanation:

x = 1st integer

x+1 = next consecutive integer

The sum is

x+ (x+1)

Combine like terms

2x+1

7 0
3 years ago
Read 2 more answers
Identify the statement that represents the given algebraic expression.
ollegr [7]

Answer:

n is -32

Step-by-step explanation:

- 17 \times 2 \: equals \:  - 32 \\  - 32 \div 2 \: equals \:  - 17

8 0
3 years ago
What is the solution to the linear equation?
KIM [24]

4b + 6 = 2 - b + 4

Combine like terms on the right side:

4b + 6 = -b + 6

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4b = -b

Add 1b to both sides:

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Divide both sides by 5:

B = 0

7 0
2 years ago
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We select n + 1 different integers from the set { 1 , 2 , ··· , 2 n } . Provethat there will alwaysbe two among the selected inte
just olya [345]

Answer:

See answer below

Step-by-step explanation:

From the set

{1,2,3,4...2n} we have 2n numbers in total , n are odd and n are even , therefore for a sample of n+1 numbers , we have at least 1 even number and 1 odd number.

Then

it the set includes 1 , the largest common divisor is 1 for 1 and the other numbers

if the set includes 3, there will be always a number that is not divisible by 3. Even we construct a set of n+1 numbers that are multiple of 3 , the largest number would be 3*(n+1)= 3*n+3 > 2*n (out of bounds) , therefore we are forced to take other number that is not divisible by 3  → the largest common divisor of that number with 3 is 1

If the set includes any other prime number → the largest common divisor of that with any other is 1

For the remaining odd numbers N, they can be factorised into other 2 odd common divisors N₂ and n₂ :

N = N₂*n₂ , since n₂ ≥ 2 →  N₂ < N

then the even N₂ also should be contained in the set

therefore also for N₂

N = N₃*n₃ →  N₃ < N₂

therefore if we continue , we would obtain a number  even Nn that has no smaller common divisors → since we cannot take all the multiples of N min ( because Nmin*(n+1)= Nmin*n+Nmin > 2*n for Nmin≥2) → there is at least a number in the sample of n+1 integers whose largest common divisor is 1

6 0
3 years ago
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