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3 years ago

11

Brian borrowed a 20 foot extension ladder to use when he paints hes house. If he sets the base of the ladder 6 feet from the hou

se, as shown below, how far up will the top of the ladder reach?round to one decimal place.

2 answers:

iren [92.7K]3 years ago

7 0

Answer:

It is 20.9feet

Step-by-step explanation:

Harlamova29_29 [7]3 years ago

3 0

Answer:19.1

Step-by-step explanation:

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If master chief has three and a half cookies, and the arbiter has five and three quarters of a cookie, how many cookies do they

nikklg [1K]

Answer:

$9\dfrac{1}{4}$

$4\dfrac{5}{8}$

Step-by-step explanation:

The master chief has three and a half cookies i.e. $3\dfrac{1}{2} = \dfrac{7}{2}$ numbers of cookies.

Again the arbiter has five and three quarters of a cookie i.e. $5\dfrac{3}{4} = \dfrac{23}{4}$ number of cookies.

Therefore, in total there are $(\dfrac{7}{2} +\dfrac{23}{4} ) = \dfrac{37}{4} = 9\dfrac{1}{4}$ numbers of cookies.

If we divide the total number of cookies in to equal parts and distribute to then then each of them will get $\dfrac{37}{4 \times 2} = \dfrac{37}{8} = 4\dfrac{5}{8}$ numbers of cookies. (Answer)

3 0

3 years ago

Consider this right triangle with given measures what is the unknown length

DIA [1.3K]

Answer:

b = 9

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

b² + 12² = 15²

b² + 144 = 225 ( subtract 144 from both sides )

b² = 81 ( take the square root of both sides )

b = $\sqrt{81}$ = 9

4 0

3 years ago

Read 2 more answers

Rudy has 10 white she sells 23 pink seashells and 21 Brown see cells if he divides the cells into equally between three friends

Alex_Xolod [135]

Answer:

Each friend will get 18 sea shells.

Step-by-step explanation:

Given:

Rudy has white sea shells = 10

Rudy has pink sea shells = 23

Rudy has brown sea shells = 21

Number of friends = 3

Rudy divides the sea shells into equally between three friends.

We need to find how many sea shells each friend can get.

Now first we find the total number sea shells.

Total number of sea shells = white sea shells + pink sea shells + brown sea shells = 10 + 23 + 21 = 54

Now to find number of sea shell each friend can get we will divide total number of sea shell with number of friends.

number of sea shell each friend can get = $\frac{\textrm{Total number of sea shells}}{\textrm{ Number of friends}} = \frac{54}{3}=18$

Hence each friend will get 18 sea shells.

8 0

3 years ago

What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?

scoray [572]

Answer:

<u /> $\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }$

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to c} x = c$

Special Limit Rule [L’Hopital’s Rule]:
$\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]:
$\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given limit</em>.

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}$

<u>Step 2: Find Limit</u>

Let's start out by <em>directly</em> evaluating the limit:

[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}$

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

[Limit] Apply Limit Rule [L' Hopital's Rule]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}$
[Limit] Differentiate [Derivative Rules and Properties]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}$
[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}$

∴ we have <em>evaluated</em> the given limit.

___

Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0

2 years ago

PLEASE HELP!! WILL GIVE BRAINLIEST FOR BEST ANSWER!! Please solve #17 and #18. If you can only answer one it's ok.

Paha777 [63]

Well for number 17 you have to multiply by two which 4 * 2 is 8 and 12 * 2= 24. for number 18 your answer would be isometry. hope that helped

5 0

3 years ago