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natima [27]
2 years ago
15

According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has _____roots. From the graph we can see that

it has_____ zeros.
Mathematics
1 answer:
Brums [2.3K]2 years ago
7 0
A quadratic equation always has 2 solutions.

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taurus [48]
2. 4/6 , 6/9
3. 2/4 , 3/6
4. 8/10 , 12/15

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6 0
3 years ago
For each system of equations, drag the true statement about its solution set to the box under the system?
natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

 of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

   coefficients of x and y are the same and the numerical terms

   are the same

- The system of equation has one solution if at least one of the

  coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

  numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0
3 years ago
I need help with this question asap pleaseeeeee
Harman [31]

Answer:

y = 3\sqrt{7}

Step-by-step explanation:

The two inner right triangles are similar, thus the ratios of corresponding sides are equal, that is

\frac{y}{9} = \frac{7}{y} ( cross- multiply )

y² = 63 ( take the square root of both sides )

y = \sqrt{63} = \sqrt{9(7)} = \sqrt{9} × \sqrt{7} = 3\sqrt{7}

6 0
3 years ago
Read 2 more answers
Need help with soh cah toa will award most brainliest
frez [133]

Answer:

46.07

Step-by-step explanation:

CAH (cosine=adjacent/hypotenuse)

cos (71)=15 (adjacent)/x (hypotenuse)

x=15/cos(71)

x=46.07

7 0
2 years ago
Read 2 more answers
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