What is x2- 10x+ 9= 0

Jonas jogged up the hill at an average rate of of a mile per minute and then walked down the hill at an average rate of of a mil

jenyasd209 [6]

The missing value depends on the speed of jonas to total miles covered by jonas.......if we were to assume that he jogged up the hill at a distance of 15minutes then the trip took him 42 min in total so the remaining travel time would be 27 minutes .....lets say he is walking down the hill at .5 miles per min,.. you shpuld multiply by 27 by .5 which is 13.5

4 0

3 years ago

Proportions in Triangles (8)

pishuonlain [190]

Answer:

not really sure maybe 12

4 0

3 years ago

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Ted likes to run long distances. He can run 20 km in 95 minutes. He wants to know how many kilometers he will go if he runs at t

kykrilka [37]

Answer: 60 Km

Step-by-step explanation: Because if you divied 95*285= 3 so you know that it will take him 3 times the amount has given to us so we just have to do 3* 20 km which is 60

-Alissa

Hope i helped sorry if this is wrong it makes sense to me but then again i am not the best at math sooo..... sorry if this is wrong but i am pretty sure it is right :/

4 0

3 years ago

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144 coins are divided equally among some children. If there were 3 children fewer, each child would have 16 coins. How many chil

enot [183]

Answer:

12

Step-by-step explanation:

144/16=9

Each child gets sixteen coins if there are nine children.

9+3=12

There are three more children so there are twelve.

8 0

3 years ago

1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)

Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that $\mu = 8, \sigma = 1.5$