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Nikitich [7]
3 years ago
6

If sin(x)=0.3090 , what is the approximate value of csc(x)?

Mathematics
2 answers:
vitfil [10]3 years ago
5 0
\sin x=0.3090\approx\dfrac13

\csc x=\dfrac1{\sin x}\implies\csc x\approx 3

which makes 3.2362 likely the best choice.
jok3333 [9.3K]3 years ago
3 0
<h2>Answer</h2>

3.2362

<h2>Explanation</h2>

To solve this, we are going to use the trig identity: csc(x)=\frac{1}{sin(x)}

We know that our problem that sin(x)=0.3090, so let's replace the value in our identity:

csc(x)=\frac{1}{sin(x)}

csc(x)=\frac{1}{0.3090}

csc(x)=3.2362

We can conclude that the approximate value of csc(x) is 3.2362.

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Answer:

\displaystyle T'(  2,4)

\displaystyle U'( 1,1)

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we current vertices of the given triangle

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remember that,

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