It is <span>reflection across y = x
</span>
So first you would substitute j and k in the expression.
7(0.5)+5-8(0.25)
3.5+5-2
It would equal 6.5
Hope this helps!
Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
</span>
Answer:
No solution
Step-by-step explanation:
Given: 
and 
Solve both inequality separately.
Subtraction property of inequality
and
Addition property of inequality
Hence, the solution of the compound inequality intersection of both solutions.
Please find attachment for number line solution.
No solution
5.37796e13 please don't waste our time.
