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mojhsa [17]
3 years ago
12

Tyrell does sit-ups every day. On Monday, he did 4 sit-ups. On Tuesday, he did 8 sit-ups, and on Wednesday, he did 12 sit-ups. B

ased on the pattern, make a conjecture about the number of sit-ups he will do on Friday.
Mathematics
2 answers:
zalisa [80]3 years ago
5 0

Answer: 20 sit ups.

Step-by-step explanation: if tyrell does situps everyday on monday he does 4 sit ups and tuesday 8 situps wendsday 12 situps thursday 16 situps friday 20 situps all u do to solve is add 4 every day.

your welcome.

liq [111]3 years ago
3 0
By Friday he should have done 20 sit-ups because every day he is doing 4 more than the last.
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In a class there are 25 students 15 are boys what percentage are girls​
tankabanditka [31]

Answer:

40%

Step-by-step explanation:

Total students = 25

Boys = 15

Girls = 25 - 15 = 10

Percent of girls = 10/25

Percent is out of 100.

=> 10/25 = x/100

=> Cross multiply

=> 25 * x = 100 * 10

=> 25x = 1000

=> 25x/25 = 1000/25

=> x = 40

So, 40% are girls

7 0
3 years ago
If three standard six-sided die were rolled with the numbers showing on each recorded, how many equally likely outcomes would be
Kazeer [188]

Answer:

216

Step-by-step explanation:

You are rolling three die three times

a die has six sides

to obtain the sample space

we would have to multiply 6 x 6  x 6

which could account for the three roles which would be equivalent to the sample space

6^3

8 0
2 years ago
Find the height of a tree of angle of elevation of its top changes from 25 degree to 50 degree as the observer advance 15m towar
Natali5045456 [20]

Answer:

  11.5 m

Step-by-step explanation:

The problem can be solved using a trig relation that relates the side opposite the angle to the side adjacent to the angle. That relation is ...

  Tan = Opposite/Adjacent

The lengths of the adjacent sides of the triangle can be found by rearranging this formula:

  Adjacent = Opposite/Tan

__

The "opposite" side of the triangle is the height of the tree, which we can represent using h. The problem statement tells us of a relation between adjacent side lengths and angles:

  h/tan(25°) -h/tan(50°) = 15 . . . . . moving 15 meters changes the angle

  h(1/tan(25°) -1/tan(50°)) = 15

  h = 15·tan(25°)·tan(50°)/(tan(50°) -tan(25°)) = 15(0.55572/0.72545)

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The height of the tree is about 11.5 meters.

7 0
3 years ago
Question:-
8090 [49]

Step-by-step explanation:

\large \rm \red{\widetilde{Taking\ RHS:-}}

\rm :\longmapsto \dfrac{1}{3 + \sqrt{7}} \ + \ \dfrac{1}{\sqrt{7} + \sqrt{5}} \ + \ \dfrac{1}{\sqrt{5} + \sqrt{3}} \ + \ \dfrac{1}{\sqrt{3} + 1}

<u>Rationalizing, we get</u>

\rm :\longmapsto \dfrac{1}{3+\sqrt7} \times \dfrac{3-\sqrt7}{3-\sqrt7} + \dfrac{1}{\sqrt7 + \sqrt5} \times \dfrac{\sqrt7 - \sqrt5}{\sqrt7 - \sqrt5}

\rm + \dfrac{1}{\sqrt5 + \sqrt3} \times \dfrac{\sqrt5 - \sqrt3}{\sqrt5-\sqrt3} + \dfrac{1}{\sqrt3 + 1} \times \dfrac{\sqrt3 - 1}{\sqrt3 -1}

\rm :\longmapsto \dfrac{3 - \sqrt7}{(3)^2 - (\sqrt7)^2}

+ \dfrac{\sqrt7 - \sqrt5}{(\sqrt7)^2 - (\sqrt5)^2}

+\dfrac{\sqrt5 - \sqrt3}{(\sqrt5)^2 - (\sqrt3)^2} +

\dfrac{\sqrt3-1}{(\sqrt3)^2 - 1^2}

7 0
3 years ago
Read 2 more answers
If p=2 and q= 5, is the value of p/q equivalent to 2/5
PIT_PIT [208]

Answer:

Yes it is

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
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