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Evaluate the expression 4(2x+y)-2y+z for x=-2, y=4 and z=-3
Before inserting the values of the variables, I recommend writing the equation in its simplest form.
First, use the distributive property and distribute 4:-
8x+4y-2y+z
Simplifying,
8x+2y+z
Now that the expression is in its simplest form, we can substitute the variables and simplify the expression.
First, write -2 in lieu of x:-
8(-2)+2y+z
-16+2y+z
Now, write 4 in lieu of y:-
-16+2(4)+z
-16+8+z
-8+z
Final step:-
write -3 in lieu of z:-
-8+(-3)
-8-3
-11
<h3>Good luck.</h3>
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Answer:
Hell earn 2 bucks join one year
<span><span>9<span>(6j+2+j)</span></span><span>9<span>(6j+2+j)</span></span></span>Add <span><span>6j</span><span>6j</span></span> and <span>jj</span> to get <span><span>7j</span><span>7j</span></span>.<span><span>9<span>(7j+2)</span></span><span>9<span>(7j+2)</span></span></span>Apply the distributive property.<span><span>9<span>(7j)</span>+9⋅2</span><span>9<span>(7j)</span>+9⋅2</span></span>Multiply <span>77</span> by <span>99</span> to get <span>6363</span>.<span><span>63j+9⋅2</span><span>63j+9⋅2</span></span>Multiply <span>99</span> by <span>22</span> to get <span>1818</span>.<span>63j+<span>18</span></span>
Answer:
There are 6 classes we find the median by finding the middle number of the 3rd highest class and 4th highest class, even if this is a decimal.
6/3 = 3+ 0.5
The process would be different if some values are the same values already on the chart total of each class.
ie) 20 31 14 22 20 31
small data like this below you can rearrange
14 20 20 22 31 31
and see that 21 is the correct value
as there are even numbers, so we choose 20 , 22
and select the middle value = 21
Step-by-step explanation:
If there is an even number of numbers locate the two middle numbers so that there is an equal number of values to the left and to the right of these two numbers. Step 3: If there is an odd number of numbers, this middle number is the median. If there is an even number of numbers add the two middles and divide by 2.
Answer:
the answer is 96 squared feet
