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liq [111]
3 years ago
8

Noah uses 1/2 of a cup of vinegar in his salad dressing recipe. How much vinegar would Noah use to make 3 1/6 recipes? Write you

r answer as a fraction or as a whole or mixed number.
(Please help me)​
Mathematics
2 answers:
telo118 [61]3 years ago
7 0

For 1 he uses half cup

For 3 1/6 of the same recipe

He would use:-1/2*3 1/6

19/12 cup of vinegar

=1 7/12(Answer)

saul85 [17]3 years ago
6 0

Answer:

1 7/12 cups

Step-by-step explanation:

1/2 x 3 1/6  =  1/2 x 19/6  =  19/12 or 1 7/12

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16/9 is the answer, just use a calculator next time or multiple 4/3 x 4/3
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Find the circumference of a circular field with a diameter of 16 yards.<br> (Let it = 3.14)
Tatiana [17]

Answer:

Hey there!

The circumference of a circle is \pi(d), where d is the diameter, and \\\pi is a constant roughly equal to 3.14.

The diameter is 16, so plugging this into the equation, we get 3.14(16)=50.24.

The circumference of the circle is 50.24 yards.

Hope this helps :)

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Which is the correct input-output table for the function f(x) = 3x2 - 1+4?
krok68 [10]

Answer:

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4 0
3 years ago
Hey What is -5t &gt; 10
yanalaym [24]

Answer: 10 (ten) is an even number

following 9 and preceding 11

Step-by-step explanation:

3 0
3 years ago
Prove or disprove (from i=0 to n) sum([2i]^4) &lt;= (4n)^4. If true use induction, else give the smallest value of n that it doe
ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for n\geq 78

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: \sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4

For n=1: \sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4

From this point we will assume that n\geq 2

As we can see, \sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4 and (4n)^4=256n^4. Then,

\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4

Now, we will use the formula for the sum of the first 4th powers:

\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}

Therefore:

\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0

and, because n \geq 0,

465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1

Observe that, because n \geq 2 and is an integer,

n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5

In concusion, the statement is true if and only if n is a non negative integer such that n\leq 77

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute  (4n)^4- \sum^{n}_{i=0} (2i)^4 for 77 and 78 you will obtain:

(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064

(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992

7 0
3 years ago
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