Answer:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
![P(c \leq X \leq d) = \frac{d - c}{b - a}](https://tex.z-dn.net/?f=P%28c%20%5Cleq%20X%20%5Cleq%20d%29%20%3D%20%5Cfrac%7Bd%20-%20c%7D%7Bb%20-%20a%7D)
A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.
We can consider 8 am = 0, and 8:30 am = 30, so ![a = 0, b = 30](https://tex.z-dn.net/?f=a%20%3D%200%2C%20b%20%3D%2030)
Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Between 15 and 25, so:
![P(15 \leq X \leq 25) = \frac{25 - 15}{30 - 0} = 0.3333](https://tex.z-dn.net/?f=P%2815%20%5Cleq%20X%20%5Cleq%2025%29%20%3D%20%5Cfrac%7B25%20-%2015%7D%7B30%20-%200%7D%20%3D%200.3333)
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Answer:
Likely, I think I havent been in this for a long time so i may be a little rusty. But anyways, I hope this helped!
Step-by-step explanation:
Answer:
It equals -941.12.... There is a thing caled a calculator you can use for that ;D
Step-by-step explanation:
I have no idea how to do this problem i dont know what a is
I don't see a table but I can give you the means to answer it yourself. The inverse function is represented by this:
![y= \frac{k}{x}](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7Bk%7D%7Bx%7D%20)
where k is your constant. You are given a k value of 4. If you solve this for k then you will get xy=4. In your tables, multiply your x value by your y value within your coordinate points and if you get a product of 4 each time you multiply x by y, then that table is your answer.