Answer: At most 9 attendees can be there.
Step-by-step explanation:
Given equation:<em> d = 8a</em> , where <em>a</em> represents the number of attendees, and the variable <em>d </em>represents the cost in dollars.
To find : the number of attendees, if Will budgets a total of $72 for his graduation picnic.
72=8a
⇒ 9 = a [divide both sides by 8]
∴ a= 9
Hence, at most 9 attendees can be there.
Answer:
3
Step-by-step explanation:
Lannister checks out 6 sets of book
Each set had the same number of books
She reads 7 books and has 11 more to go
Therefore the number of books in each set can be calculated as follows
= 11+7
= 18
18/6
= 3
Hence there are 3 books in each set
Answer: A= (3,-3) . B(4,1). C= (1,0)
Step-by-step explanation:
Heyo Kiddo. How are you doing today?
Let's figure this out.
So in number form, the equation will be looking a little like this:

To solve.

So I hope this answers your question and that you have a great day. :)
Answer:
hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to
Answer: v = 5v + 4u + 1.5sin(3t),
Step-by-step explanation:
u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1
v represents the "velocity function" i.e v = u'(t)
As v = u'(t)
<em>u' = v</em>
since <em>u' = v </em>
v' = u"
v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )
= 5v + 4u + 1.5sin(3t) ( noting that v = u' )
so v' = 5v + 4u + 1.5sin(3t)
d/dt
=
+
Given that u(1) = 1 and u'(1) = 2.5
since v = u'
v(1) = 2.5
note: the initial value for the vector valued function is given as
= ![\left[\begin{array}{ccc}1\\2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)