Answer:
Table a match with Graph 3
Table b match with Graph 2
Table c match with Graph 4
Step-by-step explanation:
<u>Table a</u>
Time is plotted on x - axis and Temp on y axis
From table a we can see that the y values(temp) decrease with increasing time. The only graph that has a decreasing trend is Graph 3
<u>Table b</u>
Time plotted on x axis, cost on y axis
Looking at the values we see that they are almost linear except for 2 values at x = 2 and 2.5 and at y = 5 and 5.3.
Ignoring values 2.5 and 5.3 we see a linear fit with a slope of 20. This means either graph 1 or graph 2
However, the graph passes through (0,0) and this is not a set of values in the table. That leaves graph 2
<u>Table c</u>
Months plotted on x axis and length of fetus on the y axis
We can see that the y values (the length) increases slowly at lower values of x(x=1 and x=2) and then increase rapidly at the mid values(x = 2 thru 6) and then slows down between months 6 and 9. Only Graph 4 fits this pattern
Answer:
slope=0
Step-by-step explanation:
Slope (m) = ΔY
/ΔX
=0
ΔX = -3 – 6 = -9
ΔY = 8 – 8 = 0
Distance (d) = √ΔX2 + ΔY2 = √81 = 9
Equation of the line:
y = 0x + 8
When x=0, y = 8
Answer:
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Step-by-step explanation:
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Answer:
52488y²
Step-by-step explanation:
first solve for 3³. then solve for 18²
3³=27
18²=324
27*324=8748
then multiply 8748 by 6y²
=52488y^2