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oksian1 [2.3K]
4 years ago
14

Which values, when placed in the box, would result in a system of equations with no solution? Select the four correct answers. y

= –2x + 4 6x + 3y = –12 –4 0 4 12
Mathematics
2 answers:
Illusion [34]4 years ago
8 0

Answer:

Step-by-step explanation:

In order for the system of equations to have no solutions, the equations must be equivalent.

The answer can be solved by trial and error or by changing the second equation to the slope-intercept form and comparing it with the first equation.

If we let

6x + 3y = a

Then, the slope intercept form is:

y = -2x + a/3

Comparing the two equations, we equate the constant term:

a/3 = 4

a = 12

laila [671]4 years ago
8 0

Answer:

-12-4 0

Step-by-step explanation:

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