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oksian1 [2.3K]
4 years ago
14

Which values, when placed in the box, would result in a system of equations with no solution? Select the four correct answers. y

= –2x + 4 6x + 3y = –12 –4 0 4 12
Mathematics
2 answers:
Illusion [34]4 years ago
8 0

Answer:

Step-by-step explanation:

In order for the system of equations to have no solutions, the equations must be equivalent.

The answer can be solved by trial and error or by changing the second equation to the slope-intercept form and comparing it with the first equation.

If we let

6x + 3y = a

Then, the slope intercept form is:

y = -2x + a/3

Comparing the two equations, we equate the constant term:

a/3 = 4

a = 12

laila [671]4 years ago
8 0

Answer:

-12-4 0

Step-by-step explanation:

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scoundrel [369]

Answer:

The formula to find the volume of a cylinder is V = πr2h

The diameter divided by 2 is the radius. 5.5 divided by 2 is 2.75

v = π2.752 16.5

V = 391.8

The answer is 391.8

I hope this helps please mark me Brainliest! Have a nice day!

8 0
3 years ago
PLEASE HELP!! (50pts)
Ad libitum [116K]

Answer:

C. 248°

Step-by-step explanation:

The arc measure of a full circle is 360 degrees.

Arc XZ measures 112 degrees.

Arcs XZ and XWZ add to a full circle, or 360 degrees.

The measure of arc XWZ = 360 degree - 112 degrees = 248 degrees

4 0
4 years ago
Read 2 more answers
I need helpppppopppppp
ElenaW [278]

Answer:

D

Step-by-step explanation:

x² + 4 ≤ 2

- x + 4 < 2

4 0
3 years ago
*FIRST ANSWER GETS BRAINLIEST*
svet-max [94.6K]

The other solution to the equation is -3.

Step-by-step explanation:

Given equation is;

5x²+bx+12=0

One solution is -4/5

We will put this solution in Eqn to get the value of b first,

5(\frac{-4}{5})^2+b(\frac{-4}{5})+12=0\\5(\frac{16}{25})+(\frac{-4b}{5})+12=0\\\frac{16}{5}-\frac{-4b}{5}=-12\\

Multiplying each term by 5

5*(\frac{16}{5})-\frac{-4b}{5}*5=-12*5\\16-4b=-60\\-4b=-60-16\\-4b=-76

Dividing both sides by -4

\frac{-4b}{-4}=\frac{-76}{-4}\\b=19

Putting b=19 in given Eqn

5x²+19x+12=0

Here,

a=5 , b=19 , c=12

Using quadratic formula,

x=\frac{-b\±\sqrt{b^2-4ac}}{2a}\\x=\frac{-(19)\±\sqrt{(19)^2-4(5)(12)}}{2(5)}\\\\x=\frac{-19\±\sqrt{361-240}}{10}\\\\x=\frac{-19\±11}{10}\\

Either,                   or,

x=\frac{-19+11}{10},\ \ \ \ \ \ x=\frac{-19-11}{10}\\x=\frac{-8}{10},\ \ \ \ \ \ \ \ \ x=\frac{-30}{10}\\x=\frac{-4}{5},\ \ \ \ \ \ \ \ \ \ x= -3

The other solution to the equation is -3.

Keywords: linear equation, quadratic formula

Learn more about quadratic formula at:

  • brainly.com/question/7128279
  • brainly.com/question/6788996

#LearnwithBrainly

6 0
3 years ago
Which is a correct first step in solving 5 – 2x &lt; 8x – 3?
Elenna [48]

Answer:

5 < 10x - 3

Step-by-step explanation:

5 - 2x < 8x - 3

Add '2x' to both the sides

5 - 2x + 2x < 8x + 2x - 3

5 < 10x - 3

3 0
3 years ago
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