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3 years ago

Can you solve a system by substitution without a given variable?

Mathematics

1 answer:

VMariaS [17]3 years ago

5 0

I think so. But, the only way you can simplify is is if you add the like terms, in this case, -4x and -11x. #1 will simplify to -15x=36. you cannot simplify the other one any further.

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A number n is no less than -3

serg [7]

Answer:

this means that n = -3 ,-2, -1, 0 1 2 3 4 5 6 7 8 9 e.t.c.

Step-by-step explanation:

4 0

2 years ago

Y=-2x+4 complete the missing value in the solution to the equation

Kisachek [45]

Im not sure but I think it’s Y/2-2 (the y and 2 is a fraction)

5 0

3 years ago

Three quarter of the students running a 100-yard race finished with an average time of 16 seconds. The remaining 25% of students

iren [92.7K]

Answer:

15 seconds

Step-by-step explanation:

Because the split id 25% and 75%, we could create another average pretending that there are four kids, one who ran in 12 seconds, and three who ran in 16.

Equation for averages: (a₁ + a₂ + a₃ + ... $a_{n}$ )/ n

Plug in: (12 + 16 + 16 + 16)/4

Add: 60/4

Divide: 15 seconds

5 0

3 years ago

Y = (x)^(1/9)*Find f(x) when x=(1/2)Round your answer to the nearest thousandth.

Verizon [17]

We are given a function f ( x ) defined as follows:

$y=f(x)=x^{\frac{1}{9}}$

We are to determine the value of f ( x ) when,

$\times\text{ = }\frac{1}{2}$

In such cases, we plug in/substitue the given value of x into the expressed function f ( x ) as follows:

$y\text{ = f ( }\frac{1}{2}\text{ ) = (}\frac{1}{2})^{\frac{1}{9}}$

We will apply the power on both numerator and denominator as follows:

$f(\frac{1}{2})=\frac{1^{\frac{1}{9}}}{2^{\frac{1}{9}}}\text{ = }\frac{1}{2^{\frac{1}{9}}}$

Now we evaluate ( 2 ) raised to the power of ( 1 / 9 ).

$f\text{ ( }\frac{1}{2}\text{ ) = }\frac{1}{1.08005}$

Next apply the division operation as follows:

$f\text{ ( }\frac{1}{2})\text{ = }0.92587$

Once, we have evaluated the answer in decimal form ( 5 decimal places ). We will round off the answer to nearest thousandths.

Rounding off to nearest thousandth means we consider the thousandth decimal place ( 3rd ). Then we have the choice of either truncating the decimal places ( 4th and onwards ). The truncation only occurs when (4th decimal place) is < 5.

However, since the (4th decimal place) = 8 > 5. Then we add ( 1 ) to the 3rd decimal place and truncate the rest of the decimal places i.e ( 4th and onwards ).

The answer to f ( 1 / 2 ) to the nearest thousandth would be:

$\textcolor{#FF7968}{f}\text{\textcolor{#FF7968}{ ( }}\textcolor{#FF7968}{\frac{1}{2})}\text{\textcolor{#FF7968}{ = 0.926}}$

6 0

11 months ago

Solve 2x^2+x-4=0 X^2+_×+_=0

natima [27]

Answer:

Hopes it helps

Step-by-step explanation:

The Quadratic Polynomial is

2 x² +x -4=0

Using the Determinant method to find the roots of this equation

For, the Quadratic equation , ax²+ b x+c=0

(b) x²+x=0

x × (x+1)=0

x=0 ∧ x+1=0

x=0 ∧ x= -1

You can look the problem in other way

the two Quadratic polynomials are

2 x²+x-4=0, ∧ x²+x=0

x²= -x

So, 2 x²+x-4=0,

→ -2 x+x-4=0

→ -x -4=0

→x= -4

∨

x² +x² +x-4=0

x²+0-4=0→→x²+x=0

→x²=4

x=√4

x=2 ∧ x=-2

As, you will put these values into the equation, you will find that these values does not satisfy both the equations.

So, there is no solution.

You can solve these two equation graphically also.

3 0

2 years ago