Answer:
13 miles.
Step-by-step explanation:
These distances form a right angled triangle with legs 4+1 = 5 and (7+5) = 12 miles and the distance between A and B is the hypotenuse.
So the distance AB^2 = 5^2 + 12^2 = 169
AB = sqrt 169 = 13 miles.
Tan(theta)=opposite/adjacent
Tan(31)=x/10
(Tan(31))10=x
X=6.0086
Answer:
h(-6) = 3(-6)² - 6(-6) + 4
= 3(36) + 36 + 4
= 148
You basically just substitute x with -6 that's all
The equation for point-slope form is:
(y - y sub 1) = m * (x - x sub 1)
So, we enter the point we have and the slope we have:
(y - 5) = 3 * (x + 1)
The answer is the third choice.
Answer:
Step-by-step explanation:
Average speed = distance/time
Trip to dry dock
Let x be the velocity
Time = 2hours
Distance = average speed ×time
Distance = x×2
Distance = 2x
Return trip
Velocity = x-5 (5 miles per hour faster on the trip there than on the return trip)
Time = 3hrs
Distance = 3(x-5)
Since the distance is the same both to and fro;
2x = 3(x-5)
2x = 3x -15
2x-3x = -15
-x = 15
x = 15
Hence the aircraft carrier's average speed on the outbound trip is 15miles/hour