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Zarrin [17]
3 years ago
12

Can someone please help me out

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0
First, we have to figure out the angles on the interior of the triangles.  Since the 90° angle and the angle next to it form a straight line, we know that they are supplementary and add up to 180°.  We would then subtract 90° from 180° to find the value of that angle, which comes out to be 90°.  Next, since the angle measuring 125° and the angle next to it are supplementary, we would repeat the same procedure: 180° - 125° = 55°.  Now that we know the values of two of the interior angles of the triangle, we can solve for the third.  The angles of a triangle should add up to 180°, so we can solve for <em>p</em> like this:

90 + 55 + <em>p</em> = 180
145 + <em>p</em> = 180
<em>p </em>= 180 - 145
<em>p</em> = 35

The value of <em>p</em> <em />is 35°.

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lyudmila [28]

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Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

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Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

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so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

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