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Anika [276]
3 years ago
12

Evaluate the following intervalsx^-4dx​

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
8 0

Answer:

simplified:

\frac{d}{x^3}

and Find the integral if that's what you also wanted:

-\frac{1}{3x^3} +3

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Answer:

\Large \boxed{\mathrm{\bold{C}}}

Step-by-step explanation:

\sf \displaystyle sin(\theta) =\frac{opposite}{hypotenuse }

\sf \displaystyle sin(L) =\frac{x}{y}

\sf \displaystyle sin(H) =\frac{x}{z}

\displaystyle \sf \frac{sinL}{z} =\frac{sinH  }{y}

\displaystyle \sf \frac{\frac{x}{y} }{z} =\frac{\frac{x}{z} }{y}

Simplifying the expression.

\sf \displaystyle \frac{x}{yz } = \frac{x}{yz} \ (true)

\displaystyle \sf \frac{z}{sinL} =\frac{y}{sinH}

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Multiplying both sides by x.

\sf yz=yz  \ (true)

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