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mrs_skeptik [129]

3 years ago

7

PLS HELPP 4x +4 - 3x=6 ?

2 answers:

maw [93]3 years ago

4 0

Answer:

2

Step-by-step explanation:

larisa86 [58]3 years ago

3 0

Answer: $2$

Step-by-step explanation:

Combine like terms: 4x + -3x = 1x:

$4 + 1x = 6$

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation:

$4 + -4 + 1x = 6 + -4$

Combine like terms: 4 + -4 = 0:

$0 + 1x = 6 + -4$

$1x = 6 + -4$

Combine like terms: 6 + -4 = 2:

$1x = 2$

Divide each side by '1':

$x = 2$

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jolli1 [7]

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3 years ago

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Solve the following inequality

Burka [1]

First we must get rid of the -3 in the denominator
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3 years ago

After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i

Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume ( $V$ ) is calculated by:

$V = \frac{4\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the tumor.

The percentage decrease in the volume of the tumor ( $\%V$ ) is expressed by:

$\%V = \frac{\Delta V}{V_{o}} \times 100\,\%$

Where:

$\Delta V$ - Absolute decrease in the volume of the tumor.

$V_{o}$ - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

$\Delta V = V_{o}-V_{f}$

$\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})$

The percentage decrease is finally simplified:

$\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%$

Given that $R_{o} = R$ and $R_{f} = 0.77\cdot R$ , the percentage decrease in the volume of tumor is:

$\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%$

$\%V = 54.34\,\%$

The volume of the tumor experimented a decrease of 54.34 percent.

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LUCKY_DIMON [66]

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How many ML are in 7L

sergeinik [125]

Hello,
7l=7×1000=7000 ml

Bye :-)

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3 years ago

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