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2 years ago

-6 - 13 I don’t get it can someone explain?

Mathematics

2 answers:

zavuch27 [327]2 years ago

5 0

Subtracting a negative number is basically just addition. Think of it as 6+13, which would be 19.

marishachu [46]2 years ago

3 0

Answer:

-19

Step-by-step explanation:

So, you can also write this equation as:

-6 + -13 = -19

For example:

You owe your friend $6.

You borrow 13 more dollars from him.

Now you owe him $19.

You have $-19 because you are in debt.

Hope I helped :)

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Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$

So, the average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

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2 years ago

My maths problems is it right not sure if I did it right. Thanks

slega [8]

#5
$78 - 31 = 47$

4 0

3 years ago

Read 2 more answers

In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population

Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

$y=a(1+r)^{t}$

Here,

y = final value

a = initial value

r = growth rate

t = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of r as follows:

$y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145$

Now, compute the time it will take the population to grow to 800 insects as follows:

$800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17$

Thus, the time it will take the population to grow to 800 insects is 17 days.

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3 years ago

If y=34 what is y50+y/60

zmey [24]

34 times 50 plus 34 divided by 60 equals 28.9

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3 years ago

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Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneou

notsponge [240]

Extraneous solutions are the values that we get when solving equations which aren't really solutions to the equation.

<h3>What are extraneous solutions?</h3>

Your information is incomplete. Therefore, an overview will be given. An extraneous solution is the root of a transformed equation which is not a root of the original equation since it was excluded from the domain of the original equation.

The reason extraneous solutions exist is simply that some operations produce extra answers, and these operations are a part of the path to solving the problem.

Learn more about equations on:

brainly.com/question/2972832

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