The probability the man will win will be 13.23%. And the probability of winning if he wins by getting at least four heads in five flips will be 36.01%.
<h3>How to find that a given condition can be modeled by binomial distribution?</h3>
Binomial distributions consist of n independent Bernoulli trials.
Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))
P(X = x) = ⁿCₓ pˣ (1 - p)⁽ⁿ⁻ˣ⁾
A man wins in a gambling game if he gets two heads in five flips of a biased coin. the probability of getting a head with the coin is 0.7.
Then we have
p = 0.7
n = 5
Then the probability the man will win will be
P(X = 2) = ⁵C₂ (0.7)² (1 - 0.7)⁽⁵⁻²⁾
P(X = 2) = 10 x 0.49 x 0.027
P(X = 2) = 0.1323
P(X = 2) = 13.23%
Then the probability of winning if he wins by getting at least four heads in five flips will be
P(X = 4) = ⁵C₄ (0.7)⁴ (1 - 0.7)⁽⁵⁻⁴⁾
P(X = 4) = 5 x 0.2401 x 0.3
P(X = 4) = 0.3601
P(X = 4) = 36.01%
Learn more about binomial distribution here:
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The answer is C. 4 to the 3rd power is 4*4*4. 4*4=16 and 16*4=64 so the answer is C.
Answer:
A
Step-by-step explanation:
i did he test got it right
<span>8a^ 3 b ^2 = 4ab^2 (2a^2)
and
12ab^ 4 = 4ab^2(3b^2)
answer: GCF = </span>4ab^2
It will be 12 for this question
