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3 years ago

13

The expression 1/2 H B1 + B2 use the area of a trapezoid with B1 and B2 representing the two bases length of a trapezoid and h r

epresenting the high find the area of a trapezoid with base length 4in and 6in and a height of 8 in

2 answers:

Oxana [17]3 years ago

7 0

Answer:

40

Step-by-step explanation:

1/2* 8 (4 + 6) equation

4 (10) simplify

40

dimulka [17.4K]3 years ago

5 0

A and D are correct.

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2 years ago

An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,

butalik [34]

Answer:

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

$r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t$

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

$s=\sqrt{r_{A}^{2}+r_{B}^{2}}$

Rate of change of such distance can be found by the deriving the expression in terms of time:

$\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }$

Where $\frac{dr_{A}}{dt} = 500\,\frac{mi}{h}$ and $\frac{dr_{B}}{dt} = 550\,\frac{mi}{h}$ , respectively. Distances of each airliner at 2:30 PM are:

$r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi$

$r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi$

The rate of change is:

$\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }$

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

6 0

3 years ago

Take away the parentheses using distributive property.<br> −2(3v − 2x -1)

Alecsey [184]

You have to multiply -2 to all of the numbers inside the parenthesis and you will have your answer. -6v+4x+2

8 0

3 years ago

Use properties to find the sum of product 8×51gb

Eddi Din [679]

8(51) = 8(50 + 1) = 8(50) + 8(1) = 400 + 8 = 408

5 0

3 years ago

2+2 ................

lutik1710 [3]

2+2 = 4. Bro it was so hard. Did i helped you?

6 0

3 years ago

Read 2 more answers