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3 years ago

13

The expression 1/2 H B1 + B2 use the area of a trapezoid with B1 and B2 representing the two bases length of a trapezoid and h r

epresenting the high find the area of a trapezoid with base length 4in and 6in and a height of 8 in

2 answers:

Oxana [17]3 years ago

7 0

Answer:

40

Step-by-step explanation:

1/2* 8 (4 + 6) equation

4 (10) simplify

40

dimulka [17.4K]3 years ago

5 0

A and D are correct.

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What’s the amplitude,period,equation of axis, and range for y=3sin[2(x+90)]?

Irina-Kira [14]

Answer:

amplitude: 3
period: π
axis: y = 0
range: [-3, +3]

Step-by-step explanation:

The amplitude is the multiplier of the sine function: 3.

The period is 2π divided by the coefficient of x: 2π/2 = π.

The equation of the axis is any added constant: y = 0.

The range is the axis value ± the amplitude value: from -3 to +3.

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3 years ago

A submarine is at a depth of 30m. It descends another 20m and then rises

rodikova [14]

the answer is 10m deep after rising

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3 years ago

I need to know How to solve it

dezoksy [38]

SohCahToa
Heard of it?
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4 0

3 years ago

Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze

Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial $4x^3+20x^2+2x-3$

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let $f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\$

$f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\$

$\text{when x=}\frac{3}{4}\\\\$

$f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\$

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots $=\frac{-b}{a}= \frac{-20}{4}=-5\\$

But $-5+\frac{1}{2}+\frac{3}{4}= \frac{-15}{4}\neq-5$

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0

2 years ago

There are 32 students in a class. Of the class, 3/8 of the students bring their own lunches. How many students bring their lunch

OverLord2011 [107]

Answer:

The number of students that bring their lunches is 12

Step-by-step explanation:

Let

x -----> the number of students that bring their lunches

y -----> the total number of students in a class

we know that

The number of students that bring their lunches divided by the total number of students in a class must be equal to 3/8

$\frac{x}{y}=\frac{3}{8}$

$x=\frac{3}{8}y$ -----> equation A

$y=32$ -----> equation B

substitute the value of y in equation A and solve for x

$x=\frac{3}{8}(32)$

$x=12$

therefore

The number of students that bring their lunches is 12

6 0

3 years ago