Ask question

Ask question

All categories

skelet666 [1.2K]

2 years ago

13

A man bought a house for 3600 Naira he repairs the house with 150 Naira if he sold the house for 4950 Naira . Find his percentag

e profit

1 answer:

kozerog [31]2 years ago

7 0

Step-by-step explanation:

profit%=

$\frac{selling \: price - cost \: price}{cost \: price} \times 100\%$

$\frac{4950 \: naira - 3600 \: naira + 150 \: naira}{3750 \: naira} \times 100\%$

$\frac{4950 - 3750}{3750} \times 100\%$

$\frac{1200}{3750} \times 100\%$

=36%

You might be interested in

The blue dot is at what level on the number line

sesenic [268]

Answer:

The dot is at positive 4.

4 0

2 years ago

Read 2 more answers

Eleven increased by three times a number equals 68) Write an equation for this situation and then find the

lubasha [3.4K]

Answer:

11+3x=68

x=19

Step-by-step explanation:

11+3x=68 is your equation.

subtract 11 from both side to get 3x alone

3x=68-11

3x=57

divide 3 from both sides to get x alone

x=57/3

x=19

19 is your number.

8 0

2 years ago

How many solutions does the equation 9x + 27 = 27 have?

cupoosta [38]

Answer:

Step-by-step explanation:

Move all terms that don't contain

x

to the right side and solve.

x

=

0

6 0

3 years ago

Is there a difference between arcsin and inverse sine?

Anna007 [38]

I hope this helps you

f(x) =sinx

f^-1(x)=arcsinx

arcsinx is inverse of sinx function

3 0

3 years ago

In the standard (x,y) coordinate plane a right triangle has vertices at (-3,4)(3,4)(3,-4) what is the length in coordinates unit

MAXImum [283]

Given:

The vertices of a right triangle are:

$(-3,4),(3,4),(3,-4)$

To find:

The length of the hypotenuse of the given right triangle.

Solution:

Let the vertices of the right triangle are $A(-3,4),B(3,4),C(3,-4)$ .

The distance formula is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(3-(-3))^2+(4-4)^2}$

$AB=\sqrt{(3+3)^2+(0)^2}$

$AB=\sqrt{(6)^2+0}$

$AB=\sqrt{36}$

$AB=6$

Similarly,

$BC=\sqrt{(3-3)^2+(-4-4)^2}$

$BC=\sqrt{(0)^2+(-8)^2}$

$BC=\sqrt{64}$

$BC=8$

And,

$AC=\sqrt{(3-(-3))^2+(-4-4)^2}$

$AC=\sqrt{(6)^2+(-8)^2}$

$AC=\sqrt{36+64}$

$AC=\sqrt{100}$

$AC=10$

Now, taking sum of squares of two smaller sides, we get

$AB^2+BC^2=6^2+8^2$

$AB^2+BC^2=36+64$

$AB^2+BC^2=100$

$AB^2+BC^2=AC^2$

By the definition of the Pythagoras theorem, AC is the hypotenuse of the given triangle.

Therefore, the length of the hypotenuse is 10 units.

6 0

3 years ago