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Luden [163]
2 years ago
14

I really need help with this before it closes

Mathematics
2 answers:
Serhud [2]2 years ago
5 0

Answer:

4\sqrt{3}

Step-by-step explanation:

Use cosine to find y:

cos(60) = y/8\sqrt{3}

solve for y:

y = 4√3

Hope this helps!

-EmV

Makovka662 [10]2 years ago
3 0

Answer: B

Step-by-step explanation:

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3 times a number xx, subtracted from 1818, is less than -90.?90. Write an inequality for the statement above. Find the solution
Evgen [1.6K]

Answer:

The solution set is: x>36

Step-by-step explanation:

We are given that we have to subtract 3 times of some number 'x' from 18 such that the resulting equation is less than -90.

this means that : 18-3x<-90

on solving the inequality by adding 3x on both side and adding 90 on both side we get that

 108<3x

now on dividing both side by 3 we get that

x>36

Hence our solution set is: x>36


5 0
3 years ago
Read 2 more answers
The square of a number is added to 6
NikAS [45]
I think the answer is x^2+6
5 0
2 years ago
Question in attachment​
denis-greek [22]

Answer:

(a) x + y = 63 OR 3x = 63

(b) 21

(c) 42

Step-by-step explanation:

Let Vijay's age be x and Ajay's be y.

Ajay is <u>twice</u> as old as Vijay

==> Ajay's age = 2 × Vijay's age

==> <u>y = 2x</u>

<h3>(a)</h3>

<u>Sum</u> of their ages = 63

==> x + y = 63

<em>Substituting</em><em> </em><em>2</em><em>x</em><em> </em><em>for</em><em> </em><em>y</em><em>:</em>

==> x + 2x = 63

==> 3x = 63

<h3>(b)</h3>

<em>Solving the above-obtained equation:</em>

<u>==> x = 21</u>

<h3>(c)</h3>

Ajay's age = 2 times that of Vijay

==> y = 2x

==> y = 2×21

<u>==> y = 42</u>

6 0
2 years ago
Can somebody divide 5,634 divided 18 <br>show work
Bumek [7]
The answer would be 313
7 0
3 years ago
Read 2 more answers
(03.02 MC)
kotykmax [81]

Answer:

The coordinates of J are missing.  Plus, I don't see options for the conclusions.  I made an imaginary point J, which you could correct to form the proper triangle.

Step-by-step explanation:

See the attachment.  Plot all the vertices, including a corrected point J and draw the resulting triangle.  It might be that AJKL is a slightly smaller, shifted version of AGHI.  Enter the correct coordinates and then compare.

4 0
2 years ago
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