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alexandr1967 [171]
3 years ago
8

Which of the following inequalities is false?

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0
D is the answer because-8 is further down the number line than -1
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Which equation is a function?
-Dominant- [34]

the answer is B -- no matter the x factor y should be single

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3 years ago
I WILL BRAINLIEST U IF U HELP ME PLEASE
andre [41]

Answer:

c and e because alternate interior angles are congruent

Step-by-step explanation:

3 0
3 years ago
Convert fractions to a fraction out of 100. <br>15/60=? <br>30/60=? <br>25/75=?
goblinko [34]
<h3>Answer:</h3>
  • 25/100
  • 50/100
  • (33 1/3)/100
<h3>Step-by-step explanation:</h3>

The numerator can be found by multiplying each of these fractions by 100. It can be helpful to reduce these fractions first.

Here, we calculate those numerators.

a) 15/60 · 100 = 1/4 · 100 = 100/4 = 25

b) 30/60 · 100 = 1/2 · 100 = 100/2 = 50

c) 25/75 · 100 = 1/3 · 100 = 100/3 = 33 1/3

Of course, the denominator is 100, so the fractions are ...

... 15/60 = 25/100

... 30/60 = 50/100

... 25/75 = (33 1/3)/100

_____

<em>Comment on this solution</em>

Effectively, we have multiplied each fraction by 1 = 100/100. That is ...

... fraction × (100/100) = (fraction × 100)/100

This changes the form, but not the value.

8 0
2 years ago
Find the domain of the function expressed by the formula: y=x^2+8
antoniya [11.8K]

Answer:

negative to positive infinity

Step-by-step explanation:

It's a parabola shifted up 8. There is an infinite amount of x's you could input.

6 0
3 years ago
I'm having a hard time with this. A new housing development extends 4 miles in one direction, makes a right turn, and then con-
Mademuasel [1]

Answer:

perimeter = 12 miles

area = 6 square miles

Step-by-step explanation:

Since it makes a right triangle, use the Pythagorean Formula.

3^2+4^2=c^2

9+16=c^2

25=c^2

5=c, so the hypotenuse of the right triangle is 5.

Perimeter = 3+4+5 = 12 miles

area = 1/2bh (1/2 base times height)

=1/2x3x4

=6

Area = 6 square miles

8 0
2 years ago
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