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katrin2010 [14]
4 years ago
14

6.051x10^5 in standard form

Mathematics
1 answer:
jonny [76]4 years ago
4 0

Answer:

605100

Step-by-step explanation:

= 6.051 × 105

(scientific notation)

= 6.051e5

(scientific e notation)

= 605.1 × 103

(engineering notation)

(thousand; prefix kilo- (k))

= 605100

(real number)

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40.185 + 0.01<br> Round your answer to the nearest<br> hundredth.
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Answer:

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Step-by-step explanation:

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John sent 1,302 text messages in 6 weeks, How many texts was he sending per week (At what rate was he sending texts per week)?​
Llana [10]

Answer:

217 text messages

Step-by-step explanation:

1302/6 = 217

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Which is the graph of f (x) = 4 (1/2) Superscript x?
miss Akunina [59]

Answer:

Option (2) is correct graph.

Step-by-step explanation:

Given:

The function to graph is given as:

f(x)=4(\frac{1}{2})^x

Now, the above function is an exponential function of the form f(x)=ka^x

Where, 'k' and 'a' are constants.

The range of an exponential function is always greater than 0.

The domain is all real numbers.

Now, for graphing it, we need to find some points on it and its end behaviour.

Now, for x = 0, the function value is given as:

f(0)=4(\frac{1}{2})^0=4

So, (0, 4) is a point on the graph.

Now, for x = 1, the function value is given as:

f(1)=4(\frac{1}{2})^1=4\times\frac{1}{2}=2

So, (1, 2) is another point on the graph.

Now, for x = 2, the function value is given as:

f(2)=4(\frac{1}{2})^2=4\times\frac{1}{4}=1

So, (2, 1) is another point on the graph.

Now, as 'x' tends to ∞, the function value tends to:

f(x\to\infty)=4\cdot\frac{1}{2}^{\infty}=\frac{4}{\infty}=0

So, as

x\to\infty,f(x)\to0\\\\x\to-\infty,f(x)\to\infty

Now, from among all the options, only option (2) fulfills all the conditions given above.

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5 0
4 years ago
The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other squar
o-na [289]

The length of each side of the larger square is 8 cm.

<u>Step-by-step explanation</u>:

Step 1 ;

  • The combined area of two squares = 80 sq.cm
  • The side of small square = x
  • The side of larger square = 2x

Step 2 :

Area of the square = a^2

Area of small square + area of large square = 80

x^2 + (2x)^2 = 80

x^2 + 4x^2 = 80

5x^2 = 80

x^2 = 80/5

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x = ±4

Step 3 :

Since length cannot be negative, the value of x= 4

∴ The length of the side of small square = 4cm

The length of the side of larger square = 2x = 8cm

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Join the zoommmmmmmmmmmmml
amm1812

Answer:

The question is imcomplete.

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There is no zoom link or real question.

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