Answer:
She bought 3 bottles of oil, and that would be a total of 21$ of oil so she should have recieved 29.00$ back so no change
Step-by-step explanation:
<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
Answer:
For average sized artwork (about 11x14" to 30x20"), the common mat width is 2". If you artwork is smaller, you might consider a 1.75 or 1.5" mat.
Step-by-step explanation:
Answer:
Option 3
Step-by-step explanation:
All equations are in slope-intercept form. 
The 'm' is the slope.
The 'b' is the y-intercept.
The slope is also known as the rate of change. So, we would have to look at what replaces 'm' and select two equations that have the same rate of change.
<em>Let's look over the equations:</em>
<h3>Equation A:</h3>
In this equation, 0.3 replaces 'm', so the rate of change for this equation is 0.3.
<h3>Equation B:</h3>
In this equation, 3 replaces 'm', so the rate of change for this equation is 3.
<h3>Equation C:</h3><h3>
</h3>
In this equation, 0.3 replaces 'm', so the rate of change for this equation is 0.3.
<h3>Equation D:</h3><h3>
</h3>
In this equation, 0.03 replaces 'm', so the rate of change for this equation is 0.03.
Equation C and equation A have 0.3 as the slope. Since the question asks for two equations that have the same rate of change, the answer would be Equations A and C, or Option 3.
We could find the error first, but if we solve the equation, we can compare our answers to find the error. So,
7x + 12 + 3x = 8
10x + 12 = 8
10x = -4
x = -4/10
x = -2/5.
When we compare the two, we see that our second line is vastly different, and we can easily isolate the mistake, finding that it occurs when they disregard the variable in the 3x term and subtract 8 by 3 rather than combining the terms 3x and 7x together.
